\(2^4\)x 5 -[131-(13-
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1 tháng 9 2017

= 16 . 5 - 131 + 13 - 16 

= 16 . 5 - 16 + 13 - 131

= 16 . 4 + 13 - 131

= 64 + 13 - 131

= 77 - 131

= -54

1 tháng 9 2017

=80-(131+3)

=80-134

=-54

\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)

\(=\frac{-7}{25}.1-\frac{18}{25}\)

\(=\frac{-7}{25}-\frac{18}{25}\)

\(=-1\)

\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)

\(=5\frac{2}{5}.\left(4\frac{2}{7}+5\frac{5}{7}\right)\)

\(=5,4.10=54\)

17 tháng 4 2019

i don't know i mới học lớp 5

bn eie mik lớp 6 nha bn

25 tháng 7 2021

a, 3 \(\frac{14}{19}\)\(\frac{13}{17}\)\(\frac{35}{43}\)+ 6\(\frac{5}{19}\)\(\frac{8}{43}\)\(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}=\)\(9+1+\frac{13}{17}=8+\frac{13}{17}=8\frac{13}{17}\)

b, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)\(=\frac{-5}{7}.1+1\frac{5}{7}\)\(=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)

Chúc bn học tốt

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)

27 tháng 4 2017

a,    6/7+5/9+8/7-2/9=(6/7+8/7)+(5/9-2/9)=14/7+3/9=2+1/3=7/3

b, 5+7/3=22/3

27 tháng 4 2017

a/ \(\frac{6}{7}+\frac{5}{9}+\frac{8}{7}-\frac{2}{9}\)

\(\left(\frac{6}{7}+\frac{8}{7}\right)+\left(\frac{5}{9}-\frac{2}{9}\right)\)

=  \(2+\frac{1}{3}\)

\(\frac{7}{3}\)

b/ 5+\(2\frac{1}{3}\)

= 5 + \(\frac{7}{3}\)

\(\frac{22}{3}\)

23 tháng 4 2019

\(\frac{2}{7}.\left(5\frac{1}{4}-3\frac{1}{4}\right)\)

\(\frac{2}{7}.2\)

\(\frac{4}{7}\)

23 tháng 4 2019

    \(\frac{2}{7}.5\frac{1}{4}-\frac{2}{7}.3\frac{1}{4}\)

=> \(\frac{2}{7}.\left(5\frac{1}{4}-3\frac{1}{4}\right)\)

=> \(\frac{2}{7}.2\)

=> \(\frac{4}{7}\)

#Hk_tốt

#Ngọc's_Ken'z

\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)

\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)

\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)

\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)

\(=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1+\frac{-5}{7}.\left(-1\right)\)

\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}-1\right)+1\)

\(=\frac{-5}{7}.0+1==0+1=1\)