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a) (x2 + 2xy + y2) : (x + y);
=(x+y)2:(x+y)
=x+y
b) (125x3 + 1) : (5x + 1);
=(5x+1)(25x2-5x+1):(5x+1)
=25x2-5x+1
c) (x2 – 2xy + y2) : (y – x).
=(x-y)2:(y-x)
=(y-x)2:(y-x)
=y-x
a) \(\left(x^2+2xy+y^2\right):\left(x+y\right)\)
\(=\left(x+y\right)^2:\left(x+y\right)\)
\(=x+y\)
b) \(\left(125x^3+1\right):\left(5x+1\right)\)
\(=\left(5x+1\right)\left(25x^2-5x+1\right):\left(5x+1\right)\)
\(=25x^2-5x+1\)
c) \(\left(x^2-2xy+y^2\right):\left(y-x\right)\)
\(=\left(x-y\right)^2:\left(y-x\right)\)
\(=\left(y-x\right)^2:\left(y-x\right)\)
\(=y-x\)
a ) \(\left(x^2+2xy+y^2\right):\left(x+y\right)\)
\(=\left(x+y\right)^2:\left(x+y\right)\)
\(=\left(x+y\right)\)
b ) \(\left(125x^3+1\right)\left(5x+1\right)\)
\(=\left[\left(5x\right)^3+1\right]:\left(5x+1\right)\)
\(=\left(5x\right)^2-5x+1\)
\(=25x^2-5x+1\)
c ) \(\left(x^2-2xy+y^2\right):\left(y-x\right)\)
\(=\left(x-y\right)^2:\left[-\left(x-y\right)\right]\)
\(=-\left(x-y\right)\)
\(=y-x\)
a) \(\left(x^2+2xy+y^2\right):\left(x+y\right)\\ =\left(x+y\right)^2:\left(x+y\right)\\ =\left(x+y\right)\)
b) \(\left(125x^3+1\right)\left(5x+1\right)\\=\left[\left(5x\right)^3+1\right]:\left(5x+1\right)\\ =\left(5x\right)^2-5x+1 \\ =25x^2-5x+1\)
c) \(\left(x^2-2xy+y^2\right):\left(y-x\right)\\ =\left(x-y\right)^2:\left[-\left(x-y\right)\right]\\ =-\left(x-y\right)\\ =y-x\)
Bài 1: Khai triển các hằng đẳng thức
a) ( x - 3 )( x2 + 3x + 9 )
= x3 - 33
= x3 - 27
b) ( 5x - 1 )( 1 + 5x + 25x2 )
= ( 5x - 1 )(25x2 + 5x + 1 )
= (5x)3 - 1
= 125x3 - 1
c) ( x2 - 1 ) ( x4 + x2 + 1 )
= (x2)3 - 1
= x6 - 1
a) ( x - 3 )( x2 + 3x + 9 )=x3-9
b) ( 5x - 1 ) ( 1 + 5x + 25x2 )=125x3-1
c) ( x2 - 1 ) ( x4 + x2 + 1 )=x6-1
\(a,5x^2-3x\left(x-2\right)\)
\(=5x^2-3x^2+6x\)
\(=2x^2+6x\)
\(b,3x\left(x-5\right)-5x\left(x+7\right)\)
\(=3x^2-15x-5x^2-35x\)
\(=-2x^2-50x\)
c, Đề ko rõ Yang Yang
\(d,7x\left(x-5\right)+3\left(x-2\right)\)
\(=7x^2-35x+3x-6\)
\(=7x^2-32x-6\)
\(e,5-4x\left(x-2\right)+4x^2\)
\(=5-4x^2+8x+4x^2\)
\(=5+8x\)
\(f,4x\left(2x-3\right)-5x\left(x-2\right)\)
\(=8x^2-12x-5x^2+10x\)
\(=3x^2-2x\)
a) (2a2+2a+1).(2a2-2a+1)-(2a2+1)2
Áp dụng hằng đẳng thức A2- B2= (A+B)(A-B)
ta có : (2a2+1)2 - (2a)2 - (2a2+1)2
= 4a2
\(a,\left(2x-y\right)^2=4x^2-4xy+y^2\)
\(b,\left(5x-7y^2\right).\left(5x+7y^2\right)=\left(25x^2-49y^4\right)\)
\(c,\left(5x-7y\right)^2.\left(5x+7y\right)^2=\left(25x^2-70xy+49x^2\right).\left(25x^2+70xy+49x^2\right)\)
\(d,\left(\frac{1}{3}x+5y\right).\left(5y-\frac{1}{3}x\right)=25y^2-\frac{1}{9}x^2\)
học tốt nha
a) (2x-y)2 = (2x)2 - 2.2x.y + y2 =4x2-4xy+y2
b)(5x-7y2).(5x+7y2) = (5x)2 - (7y2) 2 =25x2 - 49y4
câu c,d mk ko bít làm
(125x3+1):(5x+1)
= [(5x)3+1)]:(5x+1)
=(5x+1)(25x2-5x+1):(5x+1)
= 25x2-5x+1