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Gọi A là biểu thức ta có:
CÂU1 :A = 1.2+2.3+3.4+......+99.100
3A = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
3A = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100
3A = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
A = 333 300
\(75-\left(3.5^2-4.2^3\right)\)
\(=75-3.25+4.8\)
\(=75-75+32\)
\(=32\)
\(72:\left[32+\left(100-2^2.17\right):8\right]\)
\(=72:\left[32+\left(100-4.17\right):8\right]\)
\(=72:\left[32+\left(100-68\right):8\right]\)
\(=72:\left(32+32:8\right)\)
\(=72:\left(32+4\right)\)
\(=72:36\)
\(=2\)
a, 3.5^2+15.2^2-26:2
=3.25+15.4-13
=75+60-13
=135-13
=122
b, 5^3.2-100:4+2^3.5
=125.2-25+8.5
=250-25+40
=225+40
=265
a) \(2.5^2.3^2+\left\{\left[2.5^3-\left(5x+4\right).5\right]:\left(2^2.3.5\right)\right\}=453\)
\(2.25.9+\left\{\left[2.125-\left(5x+4\right).5\right]:\left(4.3.5\right)\right\}=453\)
\(50.9+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(450+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(\left[250-\left(5x+4\right).5\right]:60=453-450\)
\(\left[250-\left(5x+4\right).5\right]:60=3\)
\(250-\left(5x+4\right).5=3.60\)
\(250-\left(5x+4\right).5=180\)
\(\left(5x+4\right).5=250-180\)
\(\left(5x+4\right).5=70\)
\(5x+4=70:5\)
\(5x+4=14\)
\(5x=14-4\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
Vậy \(x=2\)
b) \(\left|x-\frac{1}{3}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=-2\\x-\frac{1}{3}=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\left(-2\right)+\frac{1}{3}\\x=2+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{7}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{7};\frac{7}{3}\right\}\)
a)\(3x=81\) \(\Leftrightarrow3^x=3^4\)
\(\Rightarrow x=4\)
b)\(4x+1+4x=90\)( Có gì đó sai sai )
c)\(5^{x-1}+3.5^{x-2}=1000\)\(\Leftrightarrow5^{5-1}+3.5^{5-2}=1000\)
\(\Rightarrow x=5\)
3x + 4 = 100 - 3.51
3x + 4 = 100 - 15
3x + 4 = 85
3x = 85 - 4
3x = 81
\(=>x=4\)
Vậy 34 = 81
Hk tốt
3x + 4 = 100 - 3.5
3x + 4 = 100 - 15
3x + 4 = 85
3x = 85 - 4
3x = 81
3x = 34
x = 4
Vậy x = 4