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3, \(x-5⋮x-1\)
\(x-1-4⋮x-1\)
\(-4⋮x-1\Rightarrow x-1\inƯ\left(-4\right)=\left\{\pm1;\pm4\right\}\)
| x - 1 | 1 | -1 | 4 | -4 |
| x | 2 | 0 | 5 | -3 |
4,\(3x+5⋮2x-1\Leftrightarrow6x+10⋮2x+1\)
\(\Leftrightarrow3\left(2x+1\right)+7⋮2x+1\Leftrightarrow7⋮2x+1\)
\(\Rightarrow2x+1\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
| 2x + 1 | 1 | -1 | 7 | -7 |
| 2x | 0 | -2 | 6 | -8 |
| x | 0 | -1 | 3 | -4 |
\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
\(1,\)
\(A=-\frac{7}{12}+\frac{12}{18}+\frac{5}{4}\)
\(=-\frac{7}{12}+\frac{2}{3}+\frac{5}{4}\)
\(=-\frac{7}{12}+\frac{8}{12}+\frac{15}{12}\)
\(=\frac{-7+8+15}{12}\)
\(=\frac{4}{3}\)
\(1,\)
\(B=\frac{1}{4}-\frac{8}{7}:8-3:\frac{3}{4}.\left(-2\right)^2\)
\(=\frac{1}{4}-\frac{8}{7}.\frac{1}{8}-3.\frac{4}{3}.4\)
\(=\frac{1}{4}-\frac{1}{7}-16\)
\(=\frac{7-4-448}{28}\)
\(=-\frac{445}{28}\)
Mình đang bận, bạn cần gấp thế à? Trả lời trong tin nhắn nhé!!!
bài 1:
a) 1/3x=-5/3
x=-5
b) x+12/5=37/15
x=1/15
c) x-1/7=-36/7
x=-5
d) 3x-1/2=0
3x=1/2
x=1/6
e) 2/5+x=1/4
x=-3/20
1.
a, => 21-x+3 < 0
=> 24-x < 0
=> x < 24
b, => 7+x > 0
=> x > -7
c, => x-1 < 0 ; x+2 > 0 ( vì x-1 < x+2 )
=> x < 1 ; x > -2
=> -2 < x < 1
Tk mk nha
a) 11/12 - ( 2/5 + x ) = 2/3
2/5 + x = 11/12 - 2/3
2/5 + x = 1/4
x = 1/4 - 2/5
x = -3/20
11/12 -(2/5 +x) = 2/3
11/12 - 2/5 - x = 2/3
31/60 - x = 2/3
x = 31/60 - 2/3
x = -3/20
b) 2x(x - 1/7) = 0
=> 2x.x - 2 . 1/7x = 0
=> 2.(x . x - 1/7x) = 0
=> x(1 - 1/7) = 0 : 2
=> x. 6/7 = 0
=> x = 0 : 6/7
=> x = 0