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a) 14x - 2.72 = 2.3.7
2.7.(x - 7) = 2.7.3
x - 7 = 3
x = 3 + 7 = 10
b) 9x + 2.32 = 34
32x + 2.32 = 32.32
32.(x + 2) = 32.32
x + 2 = 32
x = 32 - 2
x = 7
c) 10x + 22.5 = 102
10(x + 2) = 10.10
x + 2 = 10
x = 10 - 2
x = 8
(3x-24).714=2.715
=>3x-16=2.715:714
=>3x-16=2.7
=>3x=16+14
=>x=30:3
=>x=10
Vậy x=10
a,(19x+2.52):14=(13-8)2-42
(19x+2.25):14=52-42
19x+50=9.14
19x=126-50
19x=76
x=76:19=4
b,(3x-24).73=2.74
(3x-24).73=2.7.73
(3x-16).73=14.73
3x-16=14
3x=30
x=10
\(\left(3x-2^4\right).7^3=2.7^4\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}=2.7=14\)
\(\Leftrightarrow3x-16=14\Leftrightarrow3x=14+16=30\Leftrightarrow x=\dfrac{30}{3}=10\) vậy \(x=10\)
(3.x-24).73=2.74
(3.x-16).343=2.2401
(3.x-16).343=4802
3.x-16=4802:343
3.x-16=14
3.x=14+16
3.x=30
x=30:3
x=10
\(a,14-5+x=30\)
\(\Rightarrow9+x=30\Rightarrow x=30-9\)
\(\Rightarrow x=21\)
\(b,45-\left(3+x\right)=14\)
\(\Rightarrow3+x=45-14\)
\(\Rightarrow3+x=31\Rightarrow x=31-3\)
\(\Rightarrow x=28\)
\(c,18+\left(-3+x\right)-\left(44-x\right)=55\)
\(\Rightarrow18-3+x-44+x=55\)
\(\Rightarrow2x-29=55\Rightarrow2x=55+29\)
\(\Rightarrow2x=84\Rightarrow x=84:2\)
\(\Rightarrow x=42\)
\(d,\left(x-45\right).27=0\)
\(\Rightarrow x-45=0\Rightarrow x=45\)
\(14\cdot x-2\cdot7^2=2\cdot3\cdot7\)
\(\Rightarrow14x=2\cdot3\cdot7+2\cdot7^2\)
\(\Rightarrow14x=2\cdot7\left(3+7\right)\)
\(\Rightarrow14x=14\cdot10\)
\(\Rightarrow14x=140\)
\(\Rightarrow x=\dfrac{140}{14}=10\)
#Toru