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c: \(=\dfrac{7}{23}\cdot\left(\dfrac{-4}{3}-\dfrac{5}{2}\right)=\dfrac{7}{23}\cdot\dfrac{-8-15}{6}\)
\(=\dfrac{7}{23}\cdot\dfrac{-23}{6}=-\dfrac{7}{6}\)
d: \(=\dfrac{5}{7}\left(23+\dfrac{1}{4}-13-\dfrac{1}{4}\right)=\dfrac{5}{7}\cdot10=\dfrac{50}{7}\)
e: \(=\dfrac{2^5\cdot3^3\cdot5^3}{2^3\cdot3^3\cdot2^2\cdot5^2}=5\)
i: \(=\dfrac{1}{3^{10}}\cdot3^{50}-\dfrac{2^{10}}{3^{10}}:\dfrac{4^5}{3^{10}}\)
\(=3^{40}-1\)
a: \(\Leftrightarrow4^x\left(\dfrac{3}{2}+\dfrac{5}{3}\cdot4^2\right)=4^8\left(\dfrac{3}{2}+\dfrac{5}{3}\cdot4^2\right)\)
=>4^x=4^8
=>x=8
b: \(\Leftrightarrow2^x\cdot\dfrac{1}{2}+2^x\cdot2=2^{10}\left(2^2+1\right)\)
=>2^x=2^11
=>x=11
c: =>1/6*6^x+6^x*36=6^15(1+6^3)
=>6^x=6*6^15
=>x=16
d: \(\Leftrightarrow8^x\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)=8^9\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)\)
=>x=9
c: \(=\dfrac{7}{23}\cdot\dfrac{-24-45}{18}=\dfrac{7}{23}\cdot\dfrac{-69}{18}=\dfrac{7}{18}\cdot\left(-3\right)=-\dfrac{7}{6}\)
d: \(=\dfrac{7}{5}\left(23+\dfrac{1}{4}-13-\dfrac{1}{4}\right)=\dfrac{7}{5}\cdot10=14\)
e: \(=\dfrac{2^5\cdot3^3\cdot5^3}{2^3\cdot3^3\cdot2^2\cdot5^2}=5\)
i: \(=\dfrac{1}{3^{10}}\cdot3^{50}-\dfrac{2^{10}}{3^{10}}:\dfrac{4^5}{9^5}=3^{40}-1\)
=>1/6 . 6x + 6x . 62 = 67 . ( 63 + 1 )
=> 6x (1/6 +62) = 67 . 217
=>(6x+1 . 217)/6=(68.217)/6
=>6x+1.217= 68.217
=>6x+1 = 68
=>x+1=8
=>x=7
Vậy x =7
Chúc bn hc tốt
\(\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\cdot6^x\cdot6^{x+2}=6^{15}\)
\(\Rightarrow\dfrac{1}{6}\cdot6^{x+2+x}=6^{15}\)
\(\Rightarrow6^{2x+3}=6^{15}:\dfrac{1}{6}\)
\(\Rightarrow6^{2x+2}=6^{16}\)
\(\Rightarrow2x+2=16\)
\(\Rightarrow2x=16-2\)
\(\Rightarrow2x=14\)
\(\Rightarrow x=7\)
1/6 . 6x . 6x.62=615
6x+2.6=615
62x = 615/6
62x =614
=>2x = 14
=>x = 14:2
=>x = 7