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Trả lời:
\(194-24\div\left(44x-3\right)-25=145\)
\(\Leftrightarrow194-24\div\left(44x-3\right)=170\)
\(\Leftrightarrow24\div\left(44x-3\right)=24\)
\(\Leftrightarrow44x-3=1\)
\(\Leftrightarrow44x=4\)
\(\Leftrightarrow x=\frac{1}{11}\)
Vậy \(x=\frac{1}{11}\)
\(x\times\frac{1}{3}\div\frac{2}{9}-x\div5=1\frac{2}{5}\)
\(\Leftrightarrow x\times\frac{1}{3}\times\frac{9}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{3}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\left(\frac{3}{2}-\frac{1}{5}\right)=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{13}{10}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{14}{13}\)
Vậy \(x=\frac{14}{13}\)
a)x=1/2-1/4
x=1/4
Vậy..
b)x=2/5+3/4
x=23/20
vậy...
c)x=9/35:2/7
x=9/10
vậy...
d)x=5.12/25
x=12/5
vậy...
tk mk nhoaa nếu thấy đúng nha mn
a)x+1/4=1/2
x =1/2-1/4
x =1/4
b)x-3/4=2/5
x =2/5+3/4
x =23/20
c)x x 2/7=9/35
x =9/35:2/7
x =9/10
d)x : 12/25 = 5
x =5 x 12/25
x =12/5
a, 2x3x4x8x25x125= (2x3)x(4x25)x(8x125)= 6x100x1000=600000
b,42/5 +56/9+23/4+3/5+1/3+1/4= (42/5+3/5)+(23/4+1/4)+(56/9+1/3)=9+6+59/9=
a x+\(\frac{1}{2}\)=\(\frac{5}{7}\)
x=\(\frac{5}{7}\)-\(\frac{1}{2}\)
x=\(\frac{3}{14}\)
b \(\frac{25}{7}\)-x=\(\frac{8}{9}\)
x=\(\frac{25}{7}\)-\(\frac{8}{9}\)
x=\(\frac{169}{43}\)
c \(\frac{15}{11}\)*x=\(\frac{5}{3}\)
x=\(\frac{5}{3}\):\(\frac{15}{11}\)
x=\(\frac{11}{9}\)
D x*\(\frac{5}{12}\)=\(\frac{8}{9}\)
x=\(\frac{8}{9}\):\(\frac{5}{12}\)
x=\(\frac{32}{15}\)
a) \(x+\frac{1}{2}=\frac{5}{7}\)
\(x=\frac{5}{7}-\frac{1}{2}\)
\(x=\frac{10}{14}-\frac{7}{14}\)
\(x=\frac{3}{14}\)
b) \(\frac{25}{7}-x=\frac{8}{9}\)
\(x=\frac{25}{7}-\frac{8}{9}\)
\(x=\frac{225}{63}-\frac{56}{63}\)
\(x=\frac{169}{63}\)
c) \(\frac{15}{11}\cdot x=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{15}{11}\)
\(x=\frac{5}{3}\cdot\frac{11}{15}\)
\(x=\frac{11}{9}\)
d) \(x\cdot\frac{5}{12}=\frac{8}{9}\)
\(x=\frac{8}{9}:\frac{5}{12}\)
\(x=\frac{8}{9}\cdot\frac{12}{5}\)
\(x=\frac{32}{15}\)
a, = 1/2 x 2/3 x 3/4 x .... x 99/100 = 1/100
b, = 24/25 x 5/7 x 7/9 x .... x 97/99 = 24/25 x 5/99 = 8/165
a) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{100}\right)\)
=\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{99}{100}\)
=
123 < 9 x 25205