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\(E=1.2.3+2.3.4+3.4.5+...+18.19.20\)
\(4E=1.2.3.4+2.3.4.4+3.4.5.4+...+18.19.20.4\)
\(4E=1.2.3.4+2.3.4.\left(5-1\right)+3.4.5.\left(6-2\right)+...+18.19.20.\left(21-17\right)\)
\(4E=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+...+18.19.20.21-17.18.19.20\)
\(4E=18.19.20.21\)
\(4E=143640\)
\(E=\frac{143640}{4}\)
\(E=35910\)
Chúc bạn học tốt ~
\(G=2.4.6+4.6.8+6.8.10+...+18.20.22\) ( xem lại đề có nhầm dấu ko nha bn )
\(8G=2.4.6.8+4.6.8.8+6.8.10.8+...+18.20.22.8\)
\(8G=2.4.6.8+4.6.8.\left(10-2\right)+6.8.10.\left(12-4\right)+...+18.20.22\left(24-16\right)\)
\(8G=2.4.6.8+4.6.8.10-2.4.6.8+6.8.10.12-4.6.8.10+...+18.20.22.24-16.18.20.22\)
\(8G=18.20.22.24\)
\(8G=190080\)
\(G=\frac{190080}{8}\)
\(G=23760\)
Chúc bạn học tốt ~
\(A=\frac{5}{2.4.6}+\frac{5}{4.6.8}+...+\frac{5}{16.18.20}\)
\(4A=5.\left(\frac{4}{2.4.6}+\frac{4}{4.6.8}+...+\frac{4}{16.18.20}\right)\)
\(4A=5.\left(\frac{1}{2.4}-\frac{1}{4.6}+\frac{1}{4.6}-\frac{1}{6.8}+...+\frac{1}{16.18}-\frac{1}{18.20}\right)\)
\(4A=5.\left(\frac{1}{8}-\frac{1}{360}\right)\)
\(4A=5.\left(\frac{45}{360}-\frac{1}{360}\right)\)
\(4A=5.\frac{44}{360}\)
\(A=\frac{5.44}{360.4}\)
\(A=\frac{11}{72}\)
Tham khảo~
\(A=\frac{5}{2\cdot4\cdot6}+\frac{5}{4\cdot6\cdot8}+.....+\frac{5}{16\cdot18\cdot20}\)
\(\frac{4}{5}A=\frac{4}{2\cdot4\cdot6}+\frac{4}{4\cdot6\cdot8}+.........+\frac{4}{16\cdot18\cdot20}\)
\(\frac{4}{5}A=\frac{1}{2\cdot4}-\frac{1}{4\cdot6}+\frac{1}{4\cdot6}-\frac{1}{6\cdot8}+.........+\frac{1}{16\cdot18}-\frac{1}{18\cdot20}\)
\(\frac{4}{5}A=\frac{1}{2\cdot4}-\frac{1}{18\cdot20}\)
\(\frac{4}{5}A=\frac{1}{8}-\frac{1}{360}\)
\(\frac{4}{5}A=\frac{11}{90}\)
\(A=\frac{11}{90}:\frac{4}{5}=\frac{11}{72}\)
14)
\(\left(27.45+27.55\right):\left(2+4+6+...+18\right)\)
\(=\left[27\left(45+55\right)\right]:\left[\frac{\left(18+2\right)9}{2}\right]\)
\(=\left(27.100\right):90\)
\(=2700:90\)
\(=30\)
15)
\(\left(26.180-26.12\right):\left(32-18+....+8-4\right)\)
\(=26\left(180-12\right):\left(14+4+4+4+4+4+4+4\right)\)
\(=26.168:42\)
\(=84\)
\(\left(-2\right)+4+\left(-6\right)+8+...+\left(-18\right)+20\)
\(=\left[\left(-2\right)+4\right]+\left[\left(-6\right)+8\right]+...+\left[\left(-18\right)+20\right]\)(có 5 cặp)
\(=2+2+...+2\)
\(=2.5\)
\(=10\)
\(2-4-6+8+10-12-14+16+...+1994-1996-1998+2000\)\(=\left(2-4-6+8\right)+\left(10-12-14+16\right)+...+\left(1994-1996-1998+2000\right)\)\(=0+0+...+0\)
\(=0\)
B = (-2) + 4 + (-6) + 8 + ... + (-18) + 20
= [(-2) + 4] + [(-6) + 8] + ... + [(-18) + 20]
= 2 + 2 + ... + 2 (10 số hạng )
= 2 . 10 = 20
- 2 + 4 - 6 + 8 - .... - 18 + 20 = ( - 2 + 4 ) + ( - 6 + 8 ) + ( - 10 + 12 ) + ( - 14 + 16 ) + ( - 18 + 20 ) = 2 + 2 + 2 + 2 + 2 = 2 . 5 = 10
~ easy mà ~