Câu hỏi của Trương Quỳnh Trang

Question

-4/1/3.( 1/2-1/6 ) < n < -2/3.( 1/3-1/2-3/4 )

Huỳnh Quang Sang · Accepted Answer

$-4:\frac{1}{3}\left(\frac{1}{2}-\frac{1}{6}\right)< n< \frac{-2}{3}\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)$

$\Rightarrow-4\cdot3\left(\frac{3}{6}-\frac{1}{6}\right)< n< -\frac{2}{3}\left(\frac{4}{12}-\frac{6}{12}-\frac{9}{12}\right)$

$\Rightarrow-4\cdot3\cdot\frac{1}{3}< n< -\frac{2}{3}\cdot\left(-\frac{11}{12}\right)$

$\Rightarrow-4< n< -\frac{1}{3}\cdot\left(-\frac{11}{6}\right)=\frac{11}{18}$

=> $-4< n< \frac{11}{18}$

=> $-\frac{72}{18}< n< \frac{11}{18}$

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Câu trả lời:

$-4:\frac{1}{3}\left(\frac{1}{2}-\frac{1}{6}\right)< n< \frac{-2}{3}\left(\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\right)$

$\Rightarrow-4\cdot3\left(\frac{3}{6}-\frac{1}{6}\right)< n< -\frac{2}{3}\left(\frac{4}{12}-\frac{6}{12}-\frac{9}{12}\right)$

$\Rightarrow-4\cdot3\cdot\frac{1}{3}< n< -\frac{2}{3}\cdot\left(-\frac{11}{12}\right)$

$\Rightarrow-4< n< -\frac{1}{3}\cdot\left(-\frac{11}{6}\right)=\frac{11}{18}$

=> $-4< n< \frac{11}{18}$

=> $-\frac{72}{18}< n< \frac{11}{18}$

Đến đây bạn tự xét đi nhé