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(3.x-24).73=2.74
(3.x-16).343=2.2401
(3.x-16).343=4802
3.x-16=4802:343
3.x-16=14
3.x=14+16
3.x=30
x=30:3
x=10
a) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21.
b) 128 - 3 . (x + 4) = 23
3 . (x + 4) = 128 - 23
3 . (x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31.
c) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10.
d) 5x + x = 39 - 311 : 39
5x + x = 39 - 32
5x + x = 39 - 9
6x = 30
x = 30 : 6
x = 5.
a) \(\left(\dfrac{x}{3}-4\right).5=15\)
\(\Leftrightarrow\dfrac{x}{3}-4=\dfrac{15}{5}\)
\(\Leftrightarrow\dfrac{x}{3}-4=3\)
\(\Leftrightarrow\dfrac{x}{3}=3+4\)
\(\Leftrightarrow\dfrac{x}{3}=7\)
\(\Leftrightarrow x=7.3\)
\(\Leftrightarrow x=21\)
Vậy \(x=21\)
b) \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=128-23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=\dfrac{105}{3}\)
\(\Leftrightarrow x+4=35\)
\(\Leftrightarrow x=35-4\)
\(\Leftrightarrow x=31\)
Vậy \(x=31\)
c) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}\)
\(\Leftrightarrow3x-2^4=2.7\)
\(\Leftrightarrow3x-2^4=14\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=14+16\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=\dfrac{30}{3}\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
d) \(5x+x=39-3^{11}:3^9\)
\(\Leftrightarrow6x=39-3^{11-9}\)
\(\Leftrightarrow6x=39-3^2\)
\(\Leftrightarrow6x=39-9\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=\dfrac{30}{6}\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
\(\left(3.x-2^4\right)7^3=2.7^4\)
\(\left(3.x-2^4\right)=2.7^4:7^3\)
\(\left(3.x-2^4\right)=2.7\)
\(3.x-2^4=14\)
\(3x\) \(=14+2^4\)
\(x\) \(=30:3=10\)
\(\left(2+x\right)+\left(4+x\right)+\left(6+x\right)+...+\left(52+x\right)=780\)
\(\Rightarrow2+x+4+x+6+x+...+52+x=780\)
\(\Rightarrow\left(2+4+6+...+52\right)+\left\{\left[\left(52-2\right):2+1\right]x\right\}=780\)
\(\Rightarrow\) \(\left(52+2\right).\left[\left(52-2\right):2+1\right]:2+26x=780\)
\(\Rightarrow54.26:2+26x=780\)
\(\Leftrightarrow702+26x=780\)
\(\Rightarrow26x=780-702\)
\(\Rightarrow x=78:26=3\)
Ta có (2 + x) + (4 + x) + (6 + x) + ...... + (52 + x) = 780
= (x + x + x + ..... + x) + (2 + 4 + 6 + ...... + 52) = 780
= 26x + 702 = 780
= 26x = 78
= x = 3
a)
7-x-25-7=-25
-x-25=-25
-x=0
x=0
b)
(3x-24).73=2.74
3x-24 = 2.74 : 73 = 2.74-3=2.7=14
3x-16=14
3x=14+16=30
x=30:3=10
\(\left(3x-2^4\right).7^3=2.7^4\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}=2.7=14\)
\(\Leftrightarrow3x-16=14\Leftrightarrow3x=14+16=30\Leftrightarrow x=\dfrac{30}{3}=10\) vậy \(x=10\)