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Bài 1:
a: \(\left(\frac{9}{25}-2^2\right):\left(-0,2\right)\)
\(=\left(\frac{9}{25}-4\right):\left(\frac{-1}{5}\right)=\frac{-91}{25}\cdot\frac{-5}{1}=\frac{91}{5}\)
b: \(\left(-\frac15\right)^2+\frac15-2\cdot\left(-\frac12\right)^3-\frac12\)
\(=\frac{1}{25}+\frac15-2\cdot\frac{-1}{8}-\frac12\)
\(=\frac{1}{25}+\frac{5}{25}+\frac14-\frac12=\frac{6}{25}-\frac14=\frac{24}{100}-\frac{25}{100}=-\frac{1}{100}\)
c: \(\left(3-\frac14+\frac23\right)^2:2022^0\)
\(=\left(\frac{36}{12}-\frac{3}{12}+\frac{8}{12}\right)^2=\left(\frac{41}{12}\right)^2=\frac{1681}{144}\)
d: \(2^2\cdot9:\left(3\frac45+0,2\right)\)
\(=4\cdot9:\left(3,8+0,2\right)\)
\(=\frac{36}{4}=9\)
e: \(\left(\frac14+\frac23\right)^2-1\frac13=\left(\frac{3}{12}+\frac{8}{12}\right)^2-\frac43\)
\(=\left(\frac{11}{12}\right)^2-\frac43=\frac{121}{144}-\frac{192}{144}=-\frac{71}{144}\)
f: \(1:\left(-1\frac52+0,5\right)^2\)
\(=1:\left(-\frac72+\frac12\right)^2\)
\(=1:\left(-3\right)^2=\frac19\)
Bài 2:
a: \(-\frac{5}{14}+\frac38-\frac{2}{14}-\frac38+\frac12\)
\(=\left(-\frac{5}{14}-\frac{2}{14}+\frac12\right)+\left(\frac38-\frac38\right)\)
\(=\left(-\frac{7}{14}+\frac{7}{14}\right)+0=0+0=0\)
b: \(\frac{7}{15}-\frac57+\frac{23}{15}+\frac57-\frac35\)
\(=\left(\frac{7}{15}+\frac{23}{15}\right)-\frac35+\left(\frac57-\frac57\right)\)
\(=\frac{30}{15}-\frac35=2-\frac35=\frac75\)
c: \(-\frac25\cdot\frac57+\frac{-2}{5}\cdot\frac97\)
\(=-\frac25\left(\frac57+\frac97\right)=-\frac25\cdot2=-\frac45\)
d: \(\frac{55}{27}+\frac{-21}{5}+\frac{-55}{27}-\frac{-21}{5}\)
\(=\left(\frac{55}{27}-\frac{55}{27}\right)+\left(-\frac{21}{5}+\frac{21}{5}\right)\)
=0+0=0
e: \(\frac57:\left(\frac{15}{8}-\frac14\right)-\frac57:\left(\frac14+\frac12\right)\)
\(=\frac57:\left(\frac{15}{8}-\frac28\right)-\frac57:\left(\frac14+\frac24\right)\)
\(=\frac57:\frac{13}{8}-\frac57:\frac34\)
\(=\frac57\cdot\frac{8}{13}-\frac57\cdot\frac43=\frac57\left(\frac{8}{13}-\frac43\right)=\frac57\cdot\left(\frac{24}{39}-\frac{52}{39}\right)\)
\(=\frac57\cdot\frac{-28}{39}=\frac{5\cdot\left(-4\right)}{39}=-\frac{20}{39}\)
f: \(16\frac27:\left(-\frac35\right)-28\frac27:\left(-\frac35\right)\)
\(=\left(16+\frac27\right)\cdot\frac{-5}{3}-\left(28+\frac27\right)\cdot\frac{-5}{3}\)
\(=-\frac53\left(16+\frac27-28-\frac27\right)=-\frac53\cdot\left(-12\right)=20\)

Bài 1:
a: \(\left(\frac{9}{25}-2^2\right):\left(-0,2\right)\)
\(=\left(\frac{9}{25}-4\right):\left(\frac{-1}{5}\right)=\frac{-91}{25}\cdot\frac{-5}{1}=\frac{91}{5}\)
b: \(\left(-\frac15\right)^2+\frac15-2\cdot\left(-\frac12\right)^3-\frac12\)
\(=\frac{1}{25}+\frac15-2\cdot\frac{-1}{8}-\frac12\)
\(=\frac{1}{25}+\frac{5}{25}+\frac14-\frac12=\frac{6}{25}-\frac14=\frac{24}{100}-\frac{25}{100}=-\frac{1}{100}\)
c: \(\left(3-\frac14+\frac23\right)^2:2022^0\)
\(=\left(\frac{36}{12}-\frac{3}{12}+\frac{8}{12}\right)^2=\left(\frac{41}{12}\right)^2=\frac{1681}{144}\)
d: \(2^2\cdot9:\left(3\frac45+0,2\right)\)
\(=4\cdot9:\left(3,8+0,2\right)\)
\(=\frac{36}{4}=9\)
e: \(\left(\frac14+\frac23\right)^2-1\frac13=\left(\frac{3}{12}+\frac{8}{12}\right)^2-\frac43\)
\(=\left(\frac{11}{12}\right)^2-\frac43=\frac{121}{144}-\frac{192}{144}=-\frac{71}{144}\)
f: \(1:\left(-1\frac52+0,5\right)^2\)
\(=1:\left(-\frac72+\frac12\right)^2\)
\(=1:\left(-3\right)^2=\frac19\)
Bài 2:
a: \(-\frac{5}{14}+\frac38-\frac{2}{14}-\frac38+\frac12\)
\(=\left(-\frac{5}{14}-\frac{2}{14}+\frac12\right)+\left(\frac38-\frac38\right)\)
\(=\left(-\frac{7}{14}+\frac{7}{14}\right)+0=0+0=0\)
b: \(\frac{7}{15}-\frac57+\frac{23}{15}+\frac57-\frac35\)
\(=\left(\frac{7}{15}+\frac{23}{15}\right)-\frac35+\left(\frac57-\frac57\right)\)
\(=\frac{30}{15}-\frac35=2-\frac35=\frac75\)
c: \(-\frac25\cdot\frac57+\frac{-2}{5}\cdot\frac97\)
\(=-\frac25\left(\frac57+\frac97\right)=-\frac25\cdot2=-\frac45\)
d: \(\frac{55}{27}+\frac{-21}{5}+\frac{-55}{27}-\frac{-21}{5}\)
\(=\left(\frac{55}{27}-\frac{55}{27}\right)+\left(-\frac{21}{5}+\frac{21}{5}\right)\)
=0+0=0
e: \(\frac57:\left(\frac{15}{8}-\frac14\right)-\frac57:\left(\frac14+\frac12\right)\)
\(=\frac57:\left(\frac{15}{8}-\frac28\right)-\frac57:\left(\frac14+\frac24\right)\)
\(=\frac57:\frac{13}{8}-\frac57:\frac34\)
\(=\frac57\cdot\frac{8}{13}-\frac57\cdot\frac43=\frac57\left(\frac{8}{13}-\frac43\right)=\frac57\cdot\left(\frac{24}{39}-\frac{52}{39}\right)\)
\(=\frac57\cdot\frac{-28}{39}=\frac{5\cdot\left(-4\right)}{39}=-\frac{20}{39}\)
f: \(16\frac27:\left(-\frac35\right)-28\frac27:\left(-\frac35\right)\)
\(=\left(16+\frac27\right)\cdot\frac{-5}{3}-\left(28+\frac27\right)\cdot\frac{-5}{3}\)
\(=-\frac53\left(16+\frac27-28-\frac27\right)=-\frac53\cdot\left(-12\right)=20\)

\(n^2=4\)
\(\Rightarrow\left[\begin{array}{l}n=2\\ n=-2\end{array}\right.\)
vậy n=2 hoặc n=-2

Ta có: \(7,32\times33+7,32\times67\)
\(=7,32\times\left(33+67\right)\)
\(=7,32\times100=732\)
7,32 x 33 + 7,32 x 67
= 7,32 x (33 +67)
= 7,32 x 100
= 732

Yêu cho roi cho vọt
Ghét cho ngọt cho bùi
VD: Yêu cho roi cho vọt/ Ghét cho ngọt cho bùi
Về hành động đánh mắng có thể được coi là trách móc, mắng nhiếc nhưng điều đó quy ra chung cũng chỉ để tốt cho mình. Điều này dễ khiến người khác bị hiểu lầm hay xa lánh, nhưng tâm can không bị giày vò, dằn vặt.

Danh sách các bạn muốn nhờ cô đổi tên hiển thị:
Bạn nào muốn đổi tên hiển thị thì tham gia vào lớp này của cô nhé. olm-1.102018260

Năm trăm tám mươi mốt triệu sáu trăm năm mươi tám nghìn sáu trăm năm mươi mốt được viết là:
581 658 651
Bài 1:
a: \(\left(\frac{9}{25}-2^2\right):\left(-0,2\right)\)
\(=\left(\frac{9}{25}-4\right):\left(\frac{-1}{5}\right)=\frac{-91}{25}\cdot\frac{-5}{1}=\frac{91}{5}\)
b: \(\left(-\frac15\right)^2+\frac15-2\cdot\left(-\frac12\right)^3-\frac12\)
\(=\frac{1}{25}+\frac15-2\cdot\frac{-1}{8}-\frac12\)
\(=\frac{1}{25}+\frac{5}{25}+\frac14-\frac12=\frac{6}{25}-\frac14=\frac{24}{100}-\frac{25}{100}=-\frac{1}{100}\)
c: \(\left(3-\frac14+\frac23\right)^2:2022^0\)
\(=\left(\frac{36}{12}-\frac{3}{12}+\frac{8}{12}\right)^2=\left(\frac{41}{12}\right)^2=\frac{1681}{144}\)
d: \(2^2\cdot9:\left(3\frac45+0,2\right)\)
\(=4\cdot9:\left(3,8+0,2\right)\)
\(=\frac{36}{4}=9\)
e: \(\left(\frac14+\frac23\right)^2-1\frac13=\left(\frac{3}{12}+\frac{8}{12}\right)^2-\frac43\)
\(=\left(\frac{11}{12}\right)^2-\frac43=\frac{121}{144}-\frac{192}{144}=-\frac{71}{144}\)
f: \(1:\left(-1\frac52+0,5\right)^2\)
\(=1:\left(-\frac72+\frac12\right)^2\)
\(=1:\left(-3\right)^2=\frac19\)
Bài 2:
a: \(-\frac{5}{14}+\frac38-\frac{2}{14}-\frac38+\frac12\)
\(=\left(-\frac{5}{14}-\frac{2}{14}+\frac12\right)+\left(\frac38-\frac38\right)\)
\(=\left(-\frac{7}{14}+\frac{7}{14}\right)+0=0+0=0\)
b: \(\frac{7}{15}-\frac57+\frac{23}{15}+\frac57-\frac35\)
\(=\left(\frac{7}{15}+\frac{23}{15}\right)-\frac35+\left(\frac57-\frac57\right)\)
\(=\frac{30}{15}-\frac35=2-\frac35=\frac75\)
c: \(-\frac25\cdot\frac57+\frac{-2}{5}\cdot\frac97\)
\(=-\frac25\left(\frac57+\frac97\right)=-\frac25\cdot2=-\frac45\)
d: \(\frac{55}{27}+\frac{-21}{5}+\frac{-55}{27}-\frac{-21}{5}\)
\(=\left(\frac{55}{27}-\frac{55}{27}\right)+\left(-\frac{21}{5}+\frac{21}{5}\right)\)
=0+0=0
e: \(\frac57:\left(\frac{15}{8}-\frac14\right)-\frac57:\left(\frac14+\frac12\right)\)
\(=\frac57:\left(\frac{15}{8}-\frac28\right)-\frac57:\left(\frac14+\frac24\right)\)
\(=\frac57:\frac{13}{8}-\frac57:\frac34\)
\(=\frac57\cdot\frac{8}{13}-\frac57\cdot\frac43=\frac57\left(\frac{8}{13}-\frac43\right)=\frac57\cdot\left(\frac{24}{39}-\frac{52}{39}\right)\)
\(=\frac57\cdot\frac{-28}{39}=\frac{5\cdot\left(-4\right)}{39}=-\frac{20}{39}\)
f: \(16\frac27:\left(-\frac35\right)-28\frac27:\left(-\frac35\right)\)
\(=\left(16+\frac27\right)\cdot\frac{-5}{3}-\left(28+\frac27\right)\cdot\frac{-5}{3}\)
\(=-\frac53\left(16+\frac27-28-\frac27\right)=-\frac53\cdot\left(-12\right)=20\)