Câu b, c, thôi cx được ạ

Do you know a mouse which typically wears red shorts, large yellow shoes,a nd white gloves? Yes, it must
be Mickey Mouse, one of the world’s most recognizable characters. He was created by Walt Disney and
Ub Iwerks at the Walt Disney Studios in 1928 and has been the official mascot of the Walt Disney
Company. Mickey often appears alongside his girlfriend Minnie Mouse, his pet dog Pluto, his friend
Donald Duck and Goofy, and his nemesis Pete.
Mickey officially made its first public appearance in the short film Steamboat Willie (1928). It was one of
the first sound cartoons. He went on to appear in over 130 films, including The Band Concert (1935),
Brave Little Tailor (1938). Mickey appeared mostly in short films, but also occasionally in feature-length
films. Ten of Mickey’s cartoons were nominated for the Academy Award Best Animated Short Film. One
of these cartoons, Lend a Paw, won the ward in 1942. In 1978, Mickey became the first cartoon character
to have a star on the Hollywood Walk of Fame.
1. What does Micket Mouse typically wear?
A. red shorts B. large yellow shoes,a nd white gloves C. both A and B
2. What is the official mascot of the Walt Disney Company?
A. Walt Disney B. Ub Iwerks C. Mickey
3. When did Mickey officially debut?
A. 1928 B. 1935 C. 1938
4. How many Mickey’s cartoons won the Academy Award for Best Animated Short Film?
A. ten B. one C. none
5. When did Mickey become the first cartoon character to have a star on the Hollywood Walk of Fame?
A. 1938 B. 1940 C. 1978

Tôi là một người thích nghe nhạc. Nghe nhạc sẽ giúp tôi cảm

thấy sảng khoái, dễ chịu trong những lúc mệt mỏi, làm việc quá

sức, trong khi nghe nhạc cũng giúp chúng ta học được rất nhiều

điều. Thích nghe nhạc cũng rất nhiều điều thú vị. Bạn có thích

nghe nhạc không, nếu vậy, hãy kết bạn với tôi!

ko chép mạng 100%

nhưng bài có vr hơi ngắn

I'm a person who loves to listen to music. Listening to

music will help me feel refreshed, pleasant during times

of fatigue, overwork, while listening to music also helps

us learn a lot of things. Interest in listening to music is

also a lot of interesting. Do you listening to music,

if so, please make friends with me!

Theo bài ra ta cs 

\(2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2}\)

\(4y=5z\Rightarrow\frac{y}{5}=\frac{z}{4}\)

T lại cs 

\(\frac{x}{3}=\frac{y}{2}\Rightarrow\frac{x}{15}=\frac{y}{10}\left(1\right)\)

\(\frac{y}{5}=\frac{z}{4}\Rightarrow\frac{x}{10}=\frac{z}{8}\left(2\right)\)

Từ (1);(2) \(\Rightarrow\frac{x}{15}=\frac{y}{10}=\frac{z}{8}\)

ADTC dãy tỉ số bằng nhau ta cs 

\(\frac{x}{15}=\frac{y}{10}=\frac{z}{8}=\frac{2x+3y-4z}{2.15+3.10-4.8}=\frac{56}{28}=2\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{15}=2\\\frac{y}{10}=2\\\frac{z}{8}=2\end{cases}\Rightarrow\hept{\begin{cases}x=30\\y=20\\z=16\end{cases}}}\)

\(2x=3y;4y=5z\) => \(8x=12y;12y=15z\)

=>  \(\frac{8x}{120}=\frac{12y}{120}=\frac{15z}{120}\)=> \(\frac{x}{15}=\frac{y}{10}=\frac{z}{8}\)

=>   \(\frac{2x}{30}=\frac{3y}{30}=\frac{4z}{32}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có:

\(\frac{2x}{30}=\frac{3y}{30}=\frac{4z}{32}=\frac{2x+3y-4z}{30+30-32}=\frac{56}{28}\)

=> \(\frac{2x}{30}=2=>2x=60=>x=30\)

\(\frac{3y}{30}=2=>3y=60=>y=20\)

\(\frac{4z}{32}=2=>4z=64=>z=16\)

vô số bn ạ

hình như đề có j đó sai sai

5. _________ Jim owns two cars, he rarely drives to work.
A. despite B. although C. however
6. The athlete completed the race _________ his pain.
A. despite B. although C. nevertheless
7. Jane looks pretty. She, _________, seems to lack personality.
A. despite B. although C. nevertheless
8. _________ we have a slim chance to win, we won’t lose hope.
A. despite B. although C. however
9. _________ of his bad luck, he won the medal.
A. in spite B. despite C. however
10. He is friendly _________ the fact that he’s very famous.
A. despite B. although C. however

5B 6A 9A 10A

O A D x C I z B E y

Xét tam giác AOC và tam giác BOC

có OC chung

góc BOC= góc AOC (GT)

góc CBO = góc CAO = 90⁰

suy ra tam giác AOC = tam giác BOC ( cạnh huyền- góc nhọn)

suy ra AC=BC ( hai cạnh tương ứng)

b) Xét tam giác BCE và tam giác ACD

có góc EBC = góc DAC = 90⁰

AC=BC ( CMT)

góc BCE = góc ACD ( đối đỉnh)

suy ra am giác BCE =tam giác ACD (g.c.g)

suy ra CE=CD (hai cạnh tương ứng)

suy ra tam giác ECD cân tại C

c) 

1_A           2_B         3_B          4_C          5_B

6_A          7_B          8_B          9_A         10_A