\(\dfrac{11}{33}=\dfrac{11}{3.11}=\dfrac{1}{3}\)

\(\dfrac{25}{76}< \dfrac{25}{75}=\dfrac{1}{3}\)

\(\Rightarrow\dfrac{11}{33}>\dfrac{25}{76}\)

\(\Rightarrow-\dfrac{11}{33}< -\dfrac{25}{76}\)

\(\Rightarrow\dfrac{-11}{33}< \dfrac{25}{-76}\)

\(\dfrac{121212}{232323}=\dfrac{12x10101}{23x10101}=\dfrac{12}{23}=\dfrac{12.54}{23.54}=\dfrac{648}{1242}\)

\(\dfrac{4343}{5454}=\dfrac{43x101}{54x101}=\dfrac{43}{54}=\dfrac{43.23}{23.54}=\dfrac{989}{1242}\)

mà \(\dfrac{989}{1242}>\dfrac{648}{1242}\)

Nên \(\dfrac{121212}{232323}< \dfrac{4343}{5454}\)

\(\Rightarrow-\dfrac{121212}{232323}>-\dfrac{4343}{5454}\)

\(\Rightarrow\dfrac{-121212}{232323}>\dfrac{4343}{-5454}\)

Đính chính, có thể so sánh cách 2 nhanh hơn.

...\(\dfrac{12}{23}< \dfrac{12+31}{23+31}=\dfrac{43}{54}\)

\(\Rightarrow\dfrac{121212}{232323}< \dfrac{4343}{5454}\)

\(...\Rightarrow\dfrac{-121212}{232323}>\dfrac{4343}{-5454}\)

`(2x - 1)^2 = 36`

`(2x - 1)^2 = 6^2` hoặc `(2x - 1)^2 = (-6)^2`

`2x - 1 = 6` hoặc `2x - 1 = -6`

`2x = 6 + 1` hoặc `2x = -6 + 1`

`2x = 7` hoặc `2x = -5`

`x = 7 : 2` hoặc `x = -5 : 2`

`x = 3,5` hoặc `x = -2,5`

\(\left(2x-1\right)^2=36\)

\(\Rightarrow\left(2x-1\right)^2=6^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-1=6\\2x-1=-6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=7\\2x=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)

Ta có:

\(\dfrac{-1234}{1244}=-1+\dfrac{10}{1244}\)

\(\dfrac{-4321}{4331}=-1+\dfrac{10}{4331}\)

Vì \(\dfrac{10}{1244}>\dfrac{10}{4331}\)

\(\Rightarrow-1+\dfrac{10}{1244}>-1+\dfrac{10}{4331}\)

hay \(\dfrac{-1234}{1244}>\dfrac{-4321}{4331}\)

\(\dfrac{1234}{1244}< \dfrac{1234+3037}{1244+3037}=\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{1234}{1244}< \dfrac{4331}{4321}\)

\(\Rightarrow-\dfrac{1234}{1244}>-\dfrac{4331}{4321}\)

\(\Rightarrow\dfrac{-1234}{1244}>\dfrac{4331}{-4321}\)

\(\left(x^2+2\right)^2\)

\(=\left(x^2\right)^2+2\cdot x^2\cdot2+2^2\)

\(=x^4+4x^2+4\)

(x^2+2)^2= x^4++4x^2+4

Ta có:

• BM = MN = NC = 2 cm.
• BD = BC/2 = 3 cm.
• CE = BC/2 = 3 cm.

Do đó, I là trung điểm của BD và K là trung điểm của CE.

Ta có:

• IK = ID/2 = 1,5 cm.

Vậy IK = 1,5 cm.

(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x

=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5

(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x

=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5

Nhé bạn !

x=2

Điểm A nằm đâu thế bạn ?

\(\dfrac{1}{32}\) = 2^-5

\(\dfrac{1}{8}\) = 2^-3

0,5 = \(\dfrac{1}{2}\) = 2^-1

0,25 = \(\dfrac{1}{4}\) = 2^-2