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cảm ơn mn

(x + 1)/3 = 25/(-5)

(x + 1)/3 = -5

x + 1 = -5 . 3

x + 1 = -15

x = -15 - 1

x = -16

Để 17/(2m - 3) là số nguyên thì 17 ⋮ (2m - 3)

⇒ 2m - 3 ∈ Ư(17) = {-17; -1; 1; 17}

⇒ 2m ∈ {-14; 2; 4; 20}

⇒ m ∈ {-7; 1; 2; 10}

Giúp mình với cả nhà ơi 😥😥😥

Để phân số \(\dfrac{3}{a+11}\) là số nguyên ⇒ 3⋮a+11 ( a≠-11)

⇒ a+11 ϵ Ư(3)

Ta có bảng sau:

⇒ Để \(\dfrac{3}{a+11}\) là số nguyên ⇒ a ϵ {-14;-12;-10;-8)

Để 3/(a + 11) là số nguyên thì 3 ⋮ (a + 11)

⇒ a + 11 ∈ Ư(3) = {-3; -1; 1; 3}

⇒ a ∈ {-14; -12; -10; -8}

\(\dfrac{x}{24}=\dfrac{5+4}{12}\)

\(\dfrac{x}{24}=\dfrac{9}{12}\)

\(x=\dfrac{9\times24}{12}=18\)

\(\Leftrightarrow\)\(\dfrac{x}{24}\)=\(\dfrac{10}{24}\)+\(\dfrac{8}{24}\)

\(\Leftrightarrow\) \(x\) = \(10+8\)

\(\Leftrightarrow\)\(x\) = 18

(\(\dfrac{2}{7}\)\(x\) + \(\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = 1

(\(\dfrac{2}{7}x+\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) = 1 + \(\dfrac{3}{7}\)

 (\(\dfrac{2}{7}x+\dfrac{3}{7}\)): 2\(\dfrac{1}{5}\) = \(\dfrac{10}{7}\)

 \(\dfrac{2x+3}{7}\) : \(\dfrac{11}{5}\) = \(\dfrac{10}{7}\)

  \(\dfrac{2x+3}{7}\)        = \(\dfrac{10}{7}\) 

 \(\dfrac{2x+3}{7}\)          = \(\dfrac{10}{7}\times\dfrac{11}{5}\)

\(\dfrac{2x+3}{7}\)           = \(\dfrac{22}{7}\) 

2\(x\) + 3           = \(\dfrac{22}{7}\) x 7

2\(x\) + 3           = 22

2\(x\)                 = 22 - 3

2\(x\)                 = 19

\(x\)                   = \(\dfrac{19}{2}\)

Vậy \(x=\dfrac{19}{2}\)

\(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\dfrac{-5}{6}-x=\dfrac{1}{4}\)

          \(x=\dfrac{-5}{6}-\dfrac{1}{4}\)

         \(x=\dfrac{-13}{12}\)

Vậy \(x=\dfrac{-13}{12}\)

-5/6 - x = 7/12 + -4 / 12

-5/6 - x = 1/4

         x = -5/6 - 1/4

         x = -13/12

\(60\%x+\dfrac{2}{3}x=-76\\\dfrac{3}{5}x+\dfrac{2}{3}x =-76\\ x\left(\dfrac{3}{5}+\dfrac{2}{3}\right)=-76\\ x.\dfrac{3.3+2.5}{5.3}=-76\\ \dfrac{19}{15}x=-76\\ x=-76:\dfrac{19}{15}=-60\)

60% x + 2/3 x = -76

3/5 x + 2/3 x = -76

19/15 x = -76

x = -76 : 19/15

x = -60