Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(\dfrac{31}{42}\times\dfrac{17}{25}+\dfrac{31}{42}\right)\times\left(-5\right)^2\)
\(=\dfrac{31}{42}\times\left(\dfrac{17}{25}+1\right)\times25\)
\(=\dfrac{31}{42}\times\dfrac{42}{25}\times25=31\)
d: \(\left(\dfrac{2}{5}-\dfrac{2}{3}\right)-\dfrac{7}{5}=\dfrac{2}{5}-\dfrac{7}{5}-\dfrac{2}{3}=-1-\dfrac{2}{3}=-\dfrac{5}{3}\)
b: \(\dfrac{14}{13}+\left(-\dfrac{1}{13}-\dfrac{19}{20}\right)=\dfrac{14}{13}-\dfrac{1}{13}-\dfrac{19}{20}=1-\dfrac{19}{20}=\dfrac{1}{20}\)
f: \(\dfrac{7}{8}-\dfrac{3}{8}\left(1-\dfrac{2}{3}\right)\)
\(=\dfrac{7}{8}-\dfrac{3}{8}\cdot\dfrac{1}{3}\)
\(=\dfrac{7}{8}-\dfrac{1}{8}=\dfrac{6}{8}=\dfrac{3}{4}\)
\(d,\left(\dfrac{2}{5}-\dfrac{2}{3}\right)-\dfrac{7}{5}\)
\(=\dfrac{2}{5}-\dfrac{2}{3}-\dfrac{7}{5}\)
\(=\left(\dfrac{2}{5}-\dfrac{7}{5}\right)-\dfrac{2}{3}\)
\(=-1-\dfrac{2}{3}\)
\(=-\dfrac{3}{3}-\dfrac{2}{3}=-\dfrac{5}{3}\)
\(e,\dfrac{14}{13}+\left(-\dfrac{1}{13}-\dfrac{19}{20}\right)\)
\(=\dfrac{14}{13}+-\dfrac{1}{13}-\dfrac{19}{20}\)
\(=\left(\dfrac{14}{13}+-\dfrac{1}{13}\right)-\dfrac{19}{20}\)
\(=1-\dfrac{19}{20}\)
\(=\dfrac{1}{20}\)
\(f,\dfrac{7}{8}-\dfrac{3}{8}.\left(1-\dfrac{2}{3}\right)\)
\(=\dfrac{7}{8}-\dfrac{3}{8}.\dfrac{1}{3}\)
\(=\dfrac{7}{8}-\dfrac{1}{8}.1\)
\(=\dfrac{6}{8}=\dfrac{3}{4}\)
Tác động tích cực
Trồng rừng
Cải tạo đất.
Tác động tiêu cực
Sử dụng nhiều tài nguyên thiên nhiên
Đưa vào thiên nhiên nhiều khí thải độc hại
Em tham khảo nhé.
https://olm.vn/chu-de/ly-thuyet-655132
\(S=\dfrac{1}{2^1}+\dfrac{2}{2^2}+\dfrac{3}{2^3}+...+\dfrac{2002}{2^{2002}}+\dfrac{2003}{2^{2003}}\)
\(\Rightarrow2S=1+\dfrac{2}{2^1}+\dfrac{3}{2^2}+...+\dfrac{2002}{2^{2001}}+\dfrac{2003}{2^{2002}}\)
Trừ vế cho vế:
\(\Rightarrow2S-S=1+\left(\dfrac{2}{2^1}-\dfrac{1}{2^1}\right)+\left(\dfrac{3}{2^2}-\dfrac{2}{2^2}\right)+...+\left(\dfrac{2003}{2^{2002}}-\dfrac{2002}{2^{2002}}\right)-\dfrac{2003}{2^{2003}}\)
\(\Rightarrow S=1+\dfrac{1}{2^1}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2002}}-\dfrac{2003}{2^{2003}}\)
\(\Rightarrow2S=2+1+\dfrac{1}{2^1}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2001}}-\dfrac{2003}{2^{2002}}\)
Trừ vế cho vế:
\(\Rightarrow2S-S=2-\dfrac{2004}{2^{2002}}+\dfrac{2003}{2^{2003}}\)
\(\Rightarrow S=2-\dfrac{1}{2^{2003}}\left(2004.2-2003\right)\)
\(\Rightarrow S=2-\dfrac{2005}{2^{2003}}< 2\)
15: \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{x\left(x+1\right)}=\dfrac{2021}{2022}\)
=>\(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{2021}{2022}\)
=>\(1-\dfrac{1}{x+1}=\dfrac{2021}{2022}\)
=>\(\dfrac{1}{x+1}=\dfrac{1}{2022}\)
=>x+1=2022
=>x=2021
14: \(3^{x+1}+3^{x+1}\cdot4=45\)
=>\(3^x\cdot3+3^x\cdot12=45\)
=>\(3^x=3\)
=>x=1
11: \(\dfrac{13}{15}-\left(\dfrac{13}{21}+x\right)\cdot\dfrac{7}{12}=\dfrac{7}{10}\)
=>\(\dfrac{7}{12}\left(x+\dfrac{13}{21}\right)=\dfrac{13}{15}-\dfrac{7}{10}=\dfrac{1}{6}\)
=>\(x+\dfrac{13}{21}=\dfrac{1}{6}:\dfrac{7}{12}=\dfrac{1}{6}\cdot\dfrac{12}{7}=\dfrac{2}{7}\)
=>\(x=\dfrac{2}{7}-\dfrac{13}{21}=-\dfrac{7}{21}=-\dfrac{1}{3}\)
12: \(720:\left[41-\left(2x-5\right)\right]=2^2\cdot5\)
=>\(41-\left(2x-5\right)=\dfrac{720}{20}=36\)
=>2x-5=5
=>2x=10
=>x=5
9: \(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}\)
=>\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{4}{7}\)
=>\(\left\{{}\begin{matrix}x=7\\y=21\cdot\dfrac{4}{7}=12\end{matrix}\right.\)