tìm x,y nguyên dương sao cho 2x+17=y4
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12 tháng 4 2022
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PH
12 tháng 4 2022
Đường chéo nhỏ là:
15:5x4=12(cm)
Diện tích hình thoi là:
(15x12):2=90(cm2)
Đáp số:90cm2
12 tháng 4 2022
(= Thứ 6 xâo
Đoán v hoiii ...! Trúng thỳ chúng khoqq chúng thỳ thôyy
HV
5
TL:
=0-> 2x+17=18-> không có y nguyên thỏa mãn
x > 1-> 2x+17 lẻ -> y lẻ -> y4 chia 3 dư 0 hoặc 1
x=1-> y4=2+17=19 -> không có y thỏa mãn
Nếu x=2k -> y4-22k=17 -> (y2-2k)(y2+2k)=17=1.17-> y=3-> k=3-> x=6
Nếu x=2k+1 ->
2x+1=y4-16=(y2-4)(y2+4)=3k( vì 2x chia 3 dư 2)
Nếu y chia hết cho 3 thì y4-16 không chia hết cho 3 -> vô lý
HT
sai đề hay sao đấy, mình ko lm đc