(2.x-1/3)^2=4
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\(\dfrac{4}{7}\times X=\dfrac{1}{2}\\ X=\dfrac{1}{2}:\dfrac{4}{7}=\dfrac{1}{2}\times\dfrac{7}{4}=\dfrac{7}{8}\)
a/ x+65,27=72,6
x=72,6-65,27
x=7,33
b/x-43,502=21,73
x=21,73+43,502
x=65,232
c/x.6,3=187
x=187:6,3
x=29,682....
d/ 1602:x=7,2
x=1602:7,2
x=222,5
\(X+65,27=72,6\\ X=72,6-65,27=7,33\\ ---\\ X-43,502=21,73\\ X=21,73+43,502=65,232\\ ---\\ X.6,3=187\\ X=\dfrac{187}{6,3}=\dfrac{1870}{63}\\ ---\\ 1602:X=7,2\\ X=1602:7,2=222,5\)
192 = 2.96= 2. (8.12)
Vì: 12= 8+4
Vậy ao cũ có cạnh bằng 8m
Diện tích ao cũ:
8.8 = 64(m2)
25% của 120 lít bằng:
25% x 120 = 30(lít)
Đ.số: 30 lít
Chọn D
\(\dfrac{26^4}{\left(-13\right)^5}=\dfrac{13^4.2^4}{13^4.\left(-13\right)}=\dfrac{2^4}{-13}=-\dfrac{16}{13}\)
`(2x-1/3)^2=4`
\(< =>\left[{}\begin{matrix}2x-\dfrac{1}{3}=2\\2x-\dfrac{1}{3}=-2\end{matrix}\right.\\ < =>\left[{}\begin{matrix}2x=2+\dfrac{1}{3}\\2x=-2+\dfrac{1}{3}\end{matrix}\right.\\ < =>\left[{}\begin{matrix}2x=\dfrac{7}{3}\\2x=-\dfrac{5}{3}\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{7}{3}:2\\x=-\dfrac{5}{3}:2\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{7}{3}\cdot\dfrac{1}{2}\\x=-\dfrac{5}{3}\cdot\dfrac{1}{2}\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{7}{6}\\x=-\dfrac{5}{6}\end{matrix}\right.\)
\(\left(2x-\dfrac{1}{3}\right)^2=4\)
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{1}{3}=2\\2x-\dfrac{1}{3}=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=2+\dfrac{1}{3}\\2x=-2+\dfrac{1}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{3}\\2x=-\dfrac{5}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{4}\\x=-\dfrac{5}{4}\end{matrix}\right.\)