\(\left(x-\frac{1}{4}\right)^3=\left(\frac{1}{2}\right)^3\)

<=>\(x-\frac{1}{4}=\frac{1}{2}\)

\(x=\frac{1}{2}+\frac{1}{4}\)

\(x=\frac{3}{4}\)

( x + 2 ) * ( y - 5 ) = -7

TH1: X + 2 = -7                TH2: y - 5 = - 7

         x        = -7 - 2                   y      = -7 + 5

         x        = -9                        y      = -2

=> x= -9; y= -2

Gọi số cần tìm là \(\overline{abc8}\) theo đề bài

\(3x\overline{abc8}+262=\overline{8abc}\)

\(30x\overline{abc}+24+262=8000+\overline{abc}\)

\(29x\overline{abc}=7714\Rightarrow\overline{abc}=266\)

Số cần tìm là: 2668

a)2x=0+10

2x=10

x=10:2

x=5

b)7x=0+28

7x=28

x=28:7

x=4

c)3x=7+14

3x=21

x=21:3

x=7

d)3(x+2)=44-14

3(x+2)=30

x+2=30:3

x-2=10

x=10+2

x=12

8,25. x + 2,24. x – 0,49. x = 300

= (8,25+ 2,24 – 0,49). x        = 300

= 10. x                                = 300

                                        x = 300: 10

                                        x = 30

tÌM X  chứ lộn

\(2^{300}=8^{100}\)

\(3^{200}=9^{100}\)

Vậy:\(2^{300}< 9^{200}\)

44-x (3+2) = 7.2

44-x.5=14

x.5=30

x=6

\(44-x\left(3+2\right)=7x2=14\)

\(x\left(3+2\right)=44-14=30\)

\(5x=30\)

\(x=30:5=6\)

\(10^{30}=\left(10^3\right)^{10}=1000^{10}\)

\(2^{100}=\left(2^{10}\right)^{10}=1024^{10}\)

Vậy:\(10^3< 2^{100}\)