b) Tại x=14 thì:\(B\left(x\right)=x^5-15x^4+16x^3-29x^2+13x\)

\(=x^5-\left(x+1\right)x^4+\left(x+2\right)x^3-\left(2x+1\right)x^2+x\left(x-1\right)\)

\(=x^5-x^5-x^4+x^4+2x^3-2x^3-x^2+x^2-x=-x=-14\)

a) A(x)=1

cậu giúp mình nốt phần kia đc k cậu

\(\frac{-1}{6}.\frac{-15}{19}.\frac{38}{45}=\frac{1}{9}\)

\(\frac{1}{9}\)

* Bạn tham khảo 

The summer holidays are the best time to relax and enjoy with family and friends, this is a time I have always been looking forward to waiting for every year. These summer vacations are very special for me as it is my first time spending time with my colleagues. We had a good time in Vung Tau - the city with the best beaches in Vietnam. We stayed for 2 days in a small but convenient motel. The first day, we got up early to watch the sunrise on the beach. It was the brightest thing I have ever seen. After that, we swam and lay on the sand enjoying the beautiful sun and clear blue skies. We also tasted delicious seafood and fresh coconut water. Next day we took about 30 minutes to walk to Little Mountain to visit the lighthouse. But it really doesn't work! The lighthouse offers a panoramic view of Vung Tau city and is a really interesting place. On top of a small mountain, there is a huge statue of Jesus, 28 meters high, overlooking the South China Sea. This is the largest sculpture of South Vietnam. The statue's shoulder is also a series of balconies, each of which can accommodate up to six people, offering stunning views of the surrounding landscape. The weather during our stay was very nice and the locals were very friendly. We have taken a lot of photos to preserve this memorable vacation and we also bought a lot of souvenirs. I have a lot of good memories of the whole trip. All good, but what makes the trip even more wonderful is the fact that I have built stronger relationships with my colleagues.

Ta có :

\(A=\frac{x^2+2x-4}{x+1}=\frac{x\left(x+1\right)+x+1-5}{x+1}=x+1-\frac{5}{x+1}\)

Vì A thuộc Z nên 5 / x + 1 thuộc Z

\(\Rightarrow x+1\in\left\{-5;-1;1;5\right\}\)

\(\Rightarrow x\in\left\{-6;-2;0;4\right\}\)( tm n thuộc Z ; n khác - 1 ) 

a)\(\left(2x^2-3x\right)\left(5x^2-2x+1\right)\)

\(=2x^2\left(5x^2-2x+1\right)-3x\left(5x^2-2x+1\right)\)

\(=10x^4-4x^3+2x^2-15x^3+6x^2-3x\)

\(=10x^4-19x^3+8x^2-3x\)

a. \(\left(2x^2-3x\right)\left(5x^2-2x+1\right)\)

\(=10x^4-4x^3+2x^2-15x^3+6x^2-3x\)

\(=10x^4-19x^3+8x^2-3x\)

b. \(\left(2x^4-x^3+3x^2\right):\left(\frac{1}{3}x^2\right)\)

\(=\left(2x^4-x^3+3x^2\right).\frac{3}{x^2}\)

\(=0,6x^2-3x+0,9\)

tui đó

nhưng mà mới nên mới được bạc à 

level 68

bo tat ca 10 tui vang vao can  sau do lay tung tui ra neu so hien thi tren ban can la so le thi tui vua lay ra la vang that .Neu  so hien thi tren can la so chan thi tui vua lay ra la vang gia.

Đánh số các túi tiền bằng các số tự nhiên từ 1 đến 10 . Lấy ở mỗi túi số đồng tiền vàng bằng số thứ tự ghi trên túi .

Số đồng tiền này nếu là đồng tiền thật thì chúng có số cân nặng là :

( 1 + 2 + 3 + ... + 10 ) x 10 = 500 gam

Kết quả của phép trừ 550 và số chỉ khối lượng thực sau một lần cân của 55 đồng tiền giả có được này chính là số chỉ túi đựng của tiền giả

Các bạn giúp mình với 

(1/2x - 3/4)³ =(-1): (2/3)⁶

^{1/8x - 27/64 = (-1) :​​​ 64/729}

^{1/8x- 27/64 = -729/64}

^{1/8x           = - 729/64 + 27/64}

^{1/8x            = -351/32}

^{x                   =-351/32 : 1/8}

^{x                   =-351/4}