a) x² - 2xy + 5x - 10y 

= x(x - 2y) + 5(x - 2y) 

= (x + 5)(x - 2y) 

b) x(2x - 3y) - 6y² + 4xy

= x(2x - 3y) + 2y(2x - 3y) 

= (x + 2y)(2x - 3y) 

c) 8x³ + 4x² - y² - y³

= (4x² - y²) + (8x³ - y³)

= (2x - y)(2x + y) - (2x - y)(4x² + 2xy + y²) 

 = (2x - y)(-4x² - 2xy - y² + 2x + y)

d) a³ - a²b - ab² + b³

 = a²(a- b) - b²(a - b) 

= (a² - b²)(a - b) = (a - b)²(a + b) 

e) ab²c³ + 64ab² 

 = ab²(c³ + 64) 

= ab²(c + 4)(c² + 4c + 16)

f) 27x³y - a³b³y

= y[27 - (ab)³]

= y(3 - ab)(a²b² + 3ab + 9)

Bài 1. 

\(A=x^3-4x^2+4x=x\left(x^2-4x+4\right)=x\left(x-2\right)^2\)

Bài 2. 

\(x^2\left(x-3\right)-4x+12=0\)

\(\Leftrightarrow x^2\left(x-3\right)-4\left(x-3\right)=0\)

\(\Leftrightarrow\left(x^2-4\right)\left(x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=\pm2\\x=3\end{cases}}\)

Bài 1 :

A = x³ - 4x² + 4x 

A = x.( x² - 4x + 4 ) 

A = x.( x - 2)² 

Bài 2 : chịu :))) tính mãi ko ra @@

=(2x+3)^{2 -} (2x+1)²

=(2x+3-x+1) (2x+3+2x+1)

(2x+3) (2x-3)- (2x+1)²

= (2x)^2 - 3^2 - (2x+1)²

= 4x^2 - 9 - (2x+1)²

= 4x^2 -9 - 4x² - 4x -1

=(4x² - 4x²) - (9+1) - 4x

= -10 -4x

địt ko em

\(A=\left(x^2-3x-1\right)^2-12\left(x^2-3x-1\right)+27\)

\(A=\left(x^2-3x-1\right)^2-2\left(x^2-3x-1\right)6+36-9\)

\(A=\left(x^2-3x-1-6\right)^2-3^2\)

\(A=\left(x^2-3x-7\right)^2-3^2\)

\(A=\left(x^2-3x-7-3\right)\left(x^2-3x-7+3\right)\)

\(A=\left(x^2-3x-10\right)\left(x^2-3x-4\right)\)

( 2x + 3 )( 2x - 3 ) - ( 2x + 1 )²

= ( 2x )² - 3² - ( 4x² + 4x + 1 )

= 4x² - 9 - 4x² - 4x - 1 = -4x - 10

=3x²-6x-x+2 

=3x(x-2)+(x-2)

=(x+2)(3x+1)

\(3x^2-7x+2\)

\(=3x^2-6x-x+2\)

\(=3x\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(3x-1\right)\)

1,=(x+4)(x-4)

2,=(2a-1)(2a+1)

4,=(5-3y)(5+3y)

5,=(a+1-4)(a+1+4)

6,=(x-2-y)(x+2+y)

7,=(a+b-a+b)(a+b+a-b)

8,=(a+x)²

9,=(x-2)²

10,=(x-3y)²

11,=(x+2)(x²-2x+4)

12,=(a+3)(a²-3a+9)

13,=(3x-1)(9x²+9x+1)

14,=(1/2-b)(1/4+1/2b+b²)

15,=(2x-x+y)(2x+x+y)

hello Đam Mê Ngành Luật:) sửa +3 thành -3

\(4x^2+9y^2-12xy+4x-6y-3\)

\(=\left(4x^2-12xy+9y^2+4x-6y+1\right)-4\)

\(=\left(2x-3y+1\right)^2-2^2=\left(2x-3y-1\right)\left(2x-3y+3\right)\)

Đề vẫn đúng là +3 bae à :<< cậu xem lại xem

\(1,x^3-2x+x\)

\(x^3-x\)

\(x\left(x^2-1\right)\)

\(x\left(x-1\right)\left(x+1\right)\)

\(2,3x^2+6x+3-3y^2\)

\(\left(\sqrt{3}x+\sqrt{3}\right)^2-\left(\sqrt{3}y\right)^2\)

\(\left(\sqrt{3}x+\sqrt{3}-\sqrt{3}y\right)\left(\sqrt{3}x+\sqrt{3}+\sqrt{3}y\right)\)

\(3.\left(x+1-y\right)\left(x+1+y\right)\)

\(3,2xy-x^2-y^2+16\)

\(-\left(x^2-2xy+y^2-16\right)\)

\(-\left[\left(x-y\right)^2-4^2\right]\)

\(-\left[\left(x-y-4\right)\left(x-y+4\right)\right]\)