Cho Tìm số tự nhiên biết .
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\(\dfrac{4}{9}\) : \(\left(-\dfrac{1}{7}\right)\) + \(6\dfrac{5}{9}\) + \(6\dfrac{5}{19}\) : \(\left(-\dfrac{1}{7}\right)\)
= \(\dfrac{4}{9}\) . \(\left(-\dfrac{7}{1}\right)\) + \(\dfrac{59}{9}\) + \(\dfrac{119}{19}\) . \(\left(-\dfrac{7}{1}\right)\)
= \(\dfrac{-28}{9}\) + \(\dfrac{59}{9}\) + \(\dfrac{-833}{19}\)
= \(\dfrac{31}{9}\) + \(\dfrac{-833}{19}\)
= \(\dfrac{589}{171}\) + \(\dfrac{-7497}{171}\)
= \(\dfrac{-6908}{171}\)
Em nên dùng công thức toán học để mọi người hiểu đề cho đúng
\(4^x:2^6=2^8\)
\(\Rightarrow\left(2^2\right)^x:2^6=2^8\)
\(\Rightarrow2^{2x}:2^6=2^8\)
\(\Rightarrow2^{2x-6}=2^8\)
\(\Rightarrow2x-6=8\)
\(\Rightarrow2x=14\)
\(\Rightarrow x=\dfrac{14}{2}\)
\(\Rightarrow x=7\)
Bạn nên viết lại đề bài bằng công thức toán để được hỗ trợ tốt hơn.
a) A = 2004 . 2004 = 20042 > 20022 = 2002 x 2002 = B
Vậy A > B
b) C = 143 . 143 = 1432
D = 140 . 146 + 140
D = (143 - 3)(143 + 3) + 140
D = 1432 - 9 + 140 = 1432 + 131 > 1432 = C
Vậy C < D
c) E = 27 . 58 = 26 . 58 + 58 > 27 + 58 . 26 = F
Vậy E > F
\(\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{99}+\dfrac{1}{143}+\dfrac{1}{195}\\ =\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}+\dfrac{1}{195}-\dfrac{1}{63}\\ =\dfrac{1}{2}\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}+\dfrac{2}{13.15}\right)-\dfrac{1}{63}\\ =\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}\right)-\dfrac{1}{63}\\ =\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{15}\right)-\dfrac{1}{63}=\dfrac{1}{2}.\dfrac{4}{15}-\dfrac{1}{63}=\dfrac{2}{15}-\dfrac{1}{63}=\dfrac{37}{315}\)
\(0,25\cdot1\dfrac{3}{5}\cdot\left(\dfrac{5}{4}\right)^2:-\dfrac{4}{7}\)
\(=\dfrac{1}{4}\cdot\dfrac{8}{5}\cdot\dfrac{25}{16}\cdot-\dfrac{7}{4}\)
\(=\dfrac{8\cdot25\cdot-7}{4\cdot5\cdot16\cdot4}\)
\(=\dfrac{1\cdot5\cdot-7}{4\cdot1\cdot2\cdot4}\)
\(=-\dfrac{35}{32}\)
\(\left(4-\dfrac{5}{12}\right):\left(2+\dfrac{5}{24}\right)\)
\(=\dfrac{43}{12}:\dfrac{53}{24}\)
\(=\dfrac{43}{12}\cdot\dfrac{24}{53}\)
\(=\dfrac{43\cdot2}{1\cdot53}\)
\(=\dfrac{86}{53}\)
A= 1 + 5 + 52 + 5 3 + ... + 5800
5A= 5 + 52 + 53 + .... +5 800 + 5801
5A - A = 5801 - 1
4a = 5801 - 1
5801 - 1 +1 = 5n
⇒ 5801 = 5n ⇒ n = 801