phân tích đa thức thành nhân tử: 3x^3+6x^2y+3xy^2
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Sửa lại phần 2 nha
`(2x+1/2)^3= (2x)^3 + 3. (2x)^2 . 1/2 + 3.2x.(1/2)^2 + (1/2)^3 = 8x^3 + 6x^2 + 3/2 x + 1/8`
x2 - y2 + 4y Simplify ———————————— y2 + ysqt4
STEP2:Pulling out terms
2.1 Pull out factors :
y2 + ysqt4 = y • (y + sqt4)
Trying to factor a multi variable polynomial :
2.2 Factoring x2 - y2 + 4y
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Equation at the end of step2:
((((x3)-(3•(x2)))+2x)+1) x (x2-y2+4y) (((————————————————————————•d)•x)•((d•—)•y))+—————————— (((x2)-4x)+4) d y•(y+sqt4)
STEP3:
x Simplify — d
Equation at the end of step3:
((((x3)-(3•(x2)))+2x)+1) x (x2-y2+4y) (((————————————————————————•d)•x)•((d•—)•y))+—————————— (((x2)-4x)+4) d y•(y+sqt4)
STEP 4 :
Equation at the end of step4:
((((x3)-3x2)+2x)+1) (x2-y2+4y) (((———————————————————•d)•x)•xy)+—————————— (x2-4x+4) y•(y+sqt4)
STEP5:
x3 - 3x2 + 2x + 1 Simplify ————————————————— x2 - 4x + 4
Checking for a perfect cube :
5.1 x3 - 3x2 + 2x + 1 is not a perfect cube
Trying to factor by pulling out :
5.2 Factoring: x3 - 3x2 + 2x + 1
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 2x + 1
Group 2: x3 - 3x2
Pull out from each group separately :
Group 1: (2x + 1) • (1)
Group 2: (x - 3) • (x2)
-(x-4)(x+5)
=(4-x)(x+5)
=4(x+5) - x(x+5)
= 4x + 20 - x2 -5x
= (4x-5x) + 20 -x2
= -x +20 - x2
-( x - 4 )(x + 5 )
( x + 4 )(x + 5 )
x^2 + 5x + 4x + 20
chắc vậy
\(=\left(3x-3\right)\left(5-x\right)=15x-3x^2-15+3x=18x-3x^{2-15}\)
3x3 + 6x2y+ 3xy2
=3x3 + 3x2y + 3x2y + 3xy2
= 3x2(x +y) + 3xy(x +y)
=(x+y)(3x2 + 3xy)
= 3x(x+y)(x+y)
= 3x(x+y)2