5x=4y và x-y=7
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`@` `\text {Ans}`
`\downarrow`
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{7}=\dfrac{x+y+z}{5+4+7}=\dfrac{40}{16}=\dfrac{5}{2}=2,5\)
`=>`\(\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{7}=2,5\)
`=> x = 2,5. 5 = 12,5`
`y = 2,5.4 = 10`
`z = 2,5.7 = 17,5`
Vậy, `x = 12,5`; `y = 10;` `z = 17,5.`
\(\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left[\dfrac{3}{5}+\left(-\dfrac{1}{4}\right)\right]:\dfrac{3}{7}\)
\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right):\dfrac{3}{7}\)
\(=-\dfrac{7}{20}:\dfrac{3}{7}+\dfrac{7}{20}:\dfrac{3}{7}\)
\(=-\dfrac{7}{20}.\dfrac{7}{3}+\dfrac{7}{20}.\dfrac{7}{3}=\left(-\dfrac{7}{20}+\dfrac{7}{20}\right).\dfrac{7}{3}\)
\(=0.\dfrac{7}{3}=0\)
\(\dfrac{1}{3}-\dfrac{1}{3}x=\dfrac{1}{5}\cdot\dfrac{30}{7}\)
\(\Rightarrow\dfrac{1}{3}-\dfrac{1}{3}x=\dfrac{6}{7}\)
\(\Rightarrow\dfrac{1}{3}x=\dfrac{1}{3}-\dfrac{6}{7}\)
\(\Rightarrow\dfrac{1}{3}x=-\dfrac{11}{21}\)
\(\Rightarrow x=-\dfrac{11}{21}:\dfrac{1}{3}\)
\(x=-\dfrac{11}{7}\)
Vậy \(x=-\dfrac{11}{7}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{2^2}\) + \(\dfrac{1}{2^3}\) - \(\dfrac{1}{2^4}\)+...+ \(\dfrac{1}{2^{99}}\) - \(\dfrac{1}{2^{100}}\)
2A = 1 - \(\dfrac{1}{2}\) + \(\dfrac{1}{2^2}\) - \(\dfrac{1}{2^3}\) + \(\dfrac{1}{2^3}\)-...-\(\dfrac{1}{2^{99}}\)
2A + A = 1 - \(\dfrac{1}{2^{100}}\)
3A = ( 1 - \(\dfrac{1}{2^{100}}\))
A = (1 - \(\dfrac{1}{2^{100}}\)): 3
A = \(\dfrac{1}{3}\) - \(\dfrac{1}{3.2^{100}}\)
\(\dfrac{4^{18}.9^{15}}{6^{18}}=\dfrac{2^{46}.3^{30}}{2^{18}.3^{18}}=2^{46-18}.3^{30-18}=2^{28}.3^{12}\)
418 x 915 /618
=(22)18 x (32)15 /218 x 318
=236 x 330 /218 x 318
=236-18 x 330-18
=218 x 312
=(23)6 x (32)6
=86 x 96 =726
`@` `\text {Ans}`
`\downarrow`
Ta có:
\(5x=4y\Rightarrow\dfrac{x}{4}=\dfrac{y}{5}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{x-y}{4-5}=\dfrac{7}{-1}=-7\)
\(\Rightarrow\dfrac{x}{4}=\dfrac{y}{5}=-7\)
\(\Rightarrow x=-7\cdot4=-28\)
\(y=-7\cdot5=-35\)
Vậy, `x = -28; y = -35`
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