B=\(\frac{3}{4}\).\(\frac{8}{9}\).....\(\frac{2499}{2500}\)

B=\(\frac{1.3}{2^2}\).\(\frac{2.4}{3^2}\).....\(\frac{49.50}{50^2}\)

B=\(\frac{1.3.2.4....49.50}{2^2.3^2....50^2}\)

B=\(\frac{\left(1.2....49\right).\left(3.4...50\right)}{\left(2.3...50\right).\left(2.3...50\right)}\)

B=\(\frac{1}{50.2}\)=\(\frac{1}{100}\)

\(\frac{6-12a}{18-30a}=\frac{6\left(1-2a\right)}{6\left(3-5a\right)}=\frac{1-2a}{3-5a}\)

\(\frac{5-20a}{4-16a}=\frac{5\left(1-4a\right)}{4\left(1-4a\right)}=\frac{5}{4}\)

a)\(\frac{6-12a}{18-30a}\)=\(\frac{1-2a}{3-5a}\)

\(\frac{5-20a}{4-16a}\)=\(\frac{5\left(1-4a\right)}{4\left(1-4a\right)}\)=\(\frac{5}{4}\)

hình đấy bạn nhé

Chịu 😅😅😅😅

khó đến mức z lun==

là góc bẹt

35 độ

ox là tia nằm giữa oy và oz

mOn=nOp

\(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{10}=96\)

\(\Leftrightarrow2x+4x+8x+10x=96\)

\(\Leftrightarrow24x=96\)

\(\Leftrightarrow x=4\)

Vậy x = 4

\(\frac{a}{b}< \frac{a+n}{b+n}\left(n\inℕ^∗\right)\)

Thật vậy : 

\(\frac{a}{b}< \frac{a+n}{b+n}\)

\(\Leftrightarrow a\left(b+n\right)< b\left(a+n\right)\)

\(\Leftrightarrow ab+an< ab+bn\)

\(\Leftrightarrow an< bn\)

\(\Leftrightarrow\frac{an}{n}< \frac{bn}{n}\)(do \(n\ne0\))

\(\Leftrightarrow a< b\)(đúng)