\(a;0,\left(35\right)=0,3\left(53\right)>0,353\)

\(b;2,1\left(14\right)< 2,15< 2,\left(15\right)< 2,1\left(5\right)\)

20xy - 5y² + 3xy - 6x²

= (20xy + 3xy) - 5y² - 6x²

= 23xy - 5y² - 6x²

Trả lời

(2/5)⁴.(4/25)⁶.(-8/125)⁶

=(2/5)⁴.(2/5²)⁶.(-2/5³)⁶

=(-2/5)¹⁶

Chúc học tốt !

\(\left(\frac{2}{5}\right)^4.\left(\frac{4}{25}\right)^6.\left(\frac{-8}{125}\right)^6=\left(\frac{2}{5}\right)^4.\left(\frac{4}{25}\right)^6.\left(\frac{8}{25}\right)^6=\left(\frac{2}{5}\right)^4.\left[\left(\frac{2}{5}\right)^2\right]^6.\left[\left(\frac{2}{5}\right)^3\right]^6\)

\(=\left(\frac{2}{5}\right)^4.\left(\frac{2}{5}\right)^{12}.\left(\frac{2}{5}\right)^{18}\)

\(=\left(\frac{2}{5}\right)^{34}\)

\(a,\left(\frac{5}{4}\right)^2\div-\left(\frac{35}{24}\right)^2\)

\(=\frac{25}{16}\div\frac{-1225}{576}\)

\(=\frac{-36}{49}\)

b, Xin lỗi bn, mk k đc hiểu đề cho lắm!

~Study well~

#KSJ

Bổ sung cho♈♐๖ۣۜShizu _ ℒɪȿᶏ⁀ᶦᵈᵒᶫ⁹⁷ 

\(b,\text{ }25\cdot5^{-2}\cdot5^3\cdot5^0\)

\(=5^2\cdot5^{-2}\cdot5^3\cdot1\)

\(=5^3\)

(-3)⁹ x (-3)⁴x (-3)⁵

=(-3)⁹⁺⁴⁺⁵

=(-3)18

Trả lời

(-27)³.9².(-3)⁵

=(-3³)³.(3²)².(-3)⁵

=(-3)⁹.(-3)⁵.3⁴

=3¹⁴.3⁴

=>3¹⁸

Chúc học tốt !

Ta có :

\(\left|x-2\right|+\left|x-5\right|=\left|x-2\right|+\left|5-x\right|\ge\left|x-2+5-x\right|=3\)

Dấu "=" xảy ra \(\Leftrightarrow\) \(\left(x-2\right)\left(5-x\right)\ge0\)

\(\Leftrightarrow\)\(2\le x\le5\)

hoặc \(2\ge x\ge5\)( Vô lý)

Vậy \(2\le x\le5\)là giá trị thỏa mãn \(\left|x-2\right|+\left|x-5\right|=3\)

Ta có : ..........x........=.......

=>x=........

Vậy x=.......

Hok tốt !