Mik đang gấp mn ơi
Tìm X(cấu tạo số)
a.580:(X-24)=329-150.2
b.43-(24-X)=20
c.5.(X-30)+25=100
d.96:[3(X+1)=15]=2
e.X-140:35=270
ai lm nhanh nhất mik chấm điểm cho ;)))
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a) Ta có:
\(x^2-x+1\)
\(=x^2-2\cdot\dfrac{1}{2}\cdot x+\dfrac{1}{4}+\dfrac{3}{4}\)
\(=\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}\)
Mà: \(\left(x-\dfrac{1}{2}\right)^2\ge0\) và \(\dfrac{3}{4}>0\) nên
\(\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}>0\forall x\)
\(\Rightarrow x^2-x+1>0\forall x\)
\(1-2+3-4+5-6+...+2019-2020+2021\)
\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(2019-2020\right)+2021\)
\(=-1-1-1-..-1+2021\)
\(=-1\cdot1010+2021\)
\(=-1010+2021\)
\(=-1011\)
1−2+3−4+5−6+...+2019−2020+2021
=(1−2)+(3−4)+(5−6)+...+(2019−2020)+2021=(1−2)+(3−4)+(5−6)+...+(2019−2020)+2021
=−1−1−1−..−1+2021=−1−1−1−..−1+2021
=−1⋅1010+2021=−1⋅1010+2021
=−1010+2021=−1010+2021
=−1011=−1011
\(1000=2^3\cdot5^3\)
\(7200=2^5\cdot3^2\cdot5^2\)
\(810=2\cdot3^4\cdot5\)
\(8000=2^6\cdot5^3\)
1.
$3x^4-48=3(x^4-16)=3[(x^2)^2-4^2]=3(x^2-4)(x^2+4)$
$=3(x-2)(x+2)(x^2+4)$
2.
$x^3-4x^2+8x-8=(x^3-8)-(4x^2-8x)$
$=(x-2)(x^2+2x+4)-4x(x-2)=(x-2)(x^2+2x+4-4x)=(x-2)(x^2-2x+4)$
3.
$x^4-27x=x(x^3-27)=x(x^3-3^3)=x(x-3)(x^2+3x+9)$
4.
$x^4-x^3+x^2-1=(x^4-x^3)+(x^2-1)=x^3(x-1)+(x-1)(x+1)$
$=(x-1)(x^3+x+1)$
5.
$x^5+x^3-x^2-1=(x^5+x^3)-(x^2+1)=x^3(x^2+1)-(x^2+1)$
$=(x^2+1)(x^3-1)=(x^2+1)(x-1)(x^2+x+1)$
6.
$x^3+2x^2+2x+1=(x^3+x^2)+(x^2+2x+1)=x^2(x+1)+(x+1)^2$
$=(x+1)(x^2+x+1)$
7.
$x^3+x^2-4x-4=(x^3+x^2)-(4x+4)=x^2(x+1)-4(x+1)$
$=(x+1)(x^2-4)=(x+1)(x-2)(x+2)$
8.
$x^4-2x^3+2x-1=(x^4-2x^3+x^2)-(x^2-2x+1)$
$=(x^2-x)^2-(x-1)^2=x^2(x-1)^2-(x-1)^2=(x-1)^2(x^2-1)=(x-1)^2(x-1)(x+1)$
a. 580:(x-24)=329-150.2
580:(x-24)=329-300
580:(x-24)=29
x-24=580:29
x-24=20
x=20+24
x=44
b.43-(24-x)=20
24-x= 43-20
24-x=23
x=24-23
x=1
c.5.(x-30)+25=100
5.(x-30) =100-25
5.(x-30) =75
x-30 =75:5
x-30 =15
x =15+30
x =45
e.x-140:35=270
x-4=270
x=270+4
x=274
Câu d hình như đề bài sai rồi bạn