\(\dfrac{6^{13}-3\cdot6^{12}+3^{13}}{9^5\left(4^6+1\right)}\)

\(=\dfrac{2^{13}\cdot3^{13}-2^{12}\cdot3^{13}+3^{13}}{3^{10}\left(2^{12}+1\right)}\)

\(=\dfrac{3^{12}\left(2^{13}-2^{12}+1\right)}{3^{10}\left(2^{12}+1\right)}=\dfrac{3^2\cdot\left[2^{12}\left(2-1\right)+1\right]}{2^{12}+1}\)

\(=\dfrac{9\left(2^{12}+1\right)}{2^{12}+1}\)

=9

Tuổi của HLV là:

(100+12):2=56(tuổi)

cứu em vs ạ

1 It is difficult for her to go on a trip abroad now

2 I wish I had more time to take my friends to beauty sports in my hometown

3 At school, English is compulsory while French is optional

4 Although we are away from each other, we still keep in touch

5 Lan wishes she would spend her vacation in Singapore someday

6 Malaysia is divided into two regions, known as West Malaysia and East Malaysia

TK

Hello everyone! I am very happy and proud to introduce you to my family. My family consists of 3 members, which includes my parents and me. I don’t have siblings. It would be nice if I had an older one. My father’s name is Phong and he is 45 years old. My dad loves reading and drinking coffee in the morning. My mother’s name is Bich. She is a nurse, and she turns 39 this year. My mom especially loves to cook and she cooks really well. On Sunday, my parents and I usually go out to play games at the theme park. I am happy to be with my parents. I love my family very much.

Gọi mẫu số của phân số cần tìm là x

Tử số sau khi cộng thêm 1 đơn vị là 2+1=3

Phân số mới có giá trị là 1/3 nên \(\dfrac{3}{x}=\dfrac{1}{3}\)

=>\(x=3\times\dfrac{3}{1}=9\)

Vậy: Phân số cần tìm là \(\dfrac{2}{9}\)

13

Khó quá bn ah. Tính máy tính ik😂😂😂

|x|=|y|

mà x>0; y<0

nên x=-y

2x+y=-2y+y=-y

\(\left|x\right|=\left|y\right|\) và \(x>0;y< 0\)

\(\Rightarrow y=-x\)

\(\Rightarrow2x\pm x=x\)

Vậy \(2x+y=x\)

\(70,08dm^2=700800mm^2\)

\(0,0030hm^2=30m^2\)

10,07kg=10070g

5,06 tấn=5 tấn 600hg

a: \(A=1+2+2^2+...+2^{100}\)

=>\(2A=2+2^2+2^3+...+2^{101}\)

=>\(2A-A=2+2^2+...+2^{101}-1-2-...-2^{100}\)

=>\(A=2^{101}-1\)

b: Đặt \(B=5+5^3+...+5^{99}\)

=>\(25B=5^3+5^5+...+5^{101}\)

=>\(25B-B=5^3+5^5+...+5^{101}-5-5^3-...-5^{99}\)

=>\(24B=5^{101}-5\)

=>\(B=\dfrac{5^{101}-5}{24}\)