Tìm x, biết:
x- [ 1/(2.4) + 1/(4.6) + ... + 1/(98.100 ] = 1/100
Chú thích: n/n là phân số
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\(\left(-\frac{2}{4}+\frac{3}{6}\right)-\)\(\left(\frac{3}{9}-\frac{2}{6}+-\frac{2}{3}\right)\)
\(=\left(-\frac{1}{2}+\frac{1}{2}\right)-\)\(\left(\frac{1}{3}-\frac{1}{3}+-\frac{2}{3}\right)\)
\(=0-\left(0+-\frac{2}{3}\right)\)\(=0-\frac{-2}{3}=\frac{2}{3}\)
\(=\left(\frac{-1}{2}+\frac{1}{2}\right)-\left(\frac{1}{3}-\frac{1}{3}-\frac{2}{3}\right)\))
\(=0-\left(-\frac{2}{3}\right)\)
\(=\frac{2}{3}\)
=\(\frac{1}{5}+\frac{-8}{19}-\frac{-7}{30}-\frac{11}{19}+\)\(\frac{4}{5}\)
\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{-8}{19}-\frac{11}{19}\right)\)\(+\frac{7}{30}\)
\(=1+\left(-1\right)+\frac{7}{30}\)
\(=\frac{7}{30}\).
a) => 4/3x = 7/9 - 4/9 = 1/3
=> x = 1/3 : 4/3 = 1/4
b) => 5/2 - x = 9/14 : (-4/7) = -9/8
=> x = 5/2 - (-9/8) = 5/2 + 9/8 = 29/8
c) => 3x = 2 và 2/3 - 3/4 = 8/3 - 3/4 = 23/12
=> x = 23/12 : 3 = 23/36
D) => -5/6 - x = 1/4
=> x = -5/6 - 1/4 = -13/12
a) \(\dfrac{4}{9}+\dfrac{4}{3}x=\dfrac{7}{9}\)
\(\dfrac{4}{3}x=\dfrac{7}{9}-\dfrac{4}{9}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{4}{3}\)
\(x=\dfrac{1}{4}\)
b) \(\left(\dfrac{5}{2}-x\right)\left(-\dfrac{4}{7}\right)=\dfrac{9}{14}\)
\(\dfrac{5}{2}-x=\dfrac{9}{14}:\left(-\dfrac{4}{7}\right)=-\dfrac{9}{8}\)
\(x=\dfrac{5}{2}-\left(-\dfrac{9}{8}\right)\)
\(x=\dfrac{29}{8}\)
c) \(3x+\dfrac{3}{4}=2\dfrac{2}{3}\)
\(3x+\dfrac{3}{4}=\dfrac{8}{3}\)
\(3x=\dfrac{8}{3}-\dfrac{3}{4}=\dfrac{23}{12}\)
\(x=\dfrac{23}{12}:3\)
\(x=\dfrac{23}{36}\)
d) \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(-\dfrac{5}{6}-x=\dfrac{1}{4}\)
\(x=-\dfrac{5}{6}-\dfrac{1}{4}\)
\(x=-\dfrac{13}{12}\)
x=(-2-sqrt(164))/-10=(1+sqrt(41))/5=1.481
x=(-2+sqrt(164))/-10=(1-sqrt(41))/5=-1.081
kích cho minh nha
\(x-\dfrac{1}{2}\left(\dfrac{2}{2.4}+\dfrac{2}{4.6}+...+\dfrac{2}{98.100}\right)=\dfrac{1}{100}\)
\(x-\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{98}-\dfrac{1}{100}\right)=\dfrac{1}{100}\)
\(x-\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{100}\right)=\dfrac{1}{100}\)
\(x=\dfrac{51}{200}\)