\(\left|12\right|=\pm12\)

\(\left|-12\right|=12\)

\(\left|\frac{5}{3}\right|=\pm\frac{5}{3}\)

\(\left|-\frac{4}{7}\right|=\frac{4}{7}\)

\(\left|0\right|=\pm0\)

Sửa: \(\left|12\right|=12;\left|-12\right|=12;\left|\frac{5}{3}\right|=\frac{5}{3};\left|-\frac{4}{7}\right|=\frac{4}{7};\left|0\right|=0\)

5;3;6;1\7;10;23\5;1\2

theo thứ tự là :

5;3;6;1/7;10;23/5;0,5

\(\frac{13x-2}{2x+5}=-\frac{27}{5-x}\)ĐK : \(x\ne-\frac{5}{2};5\)

\(\Rightarrow\left(13x-2\right)\left(5-x\right)=-27\left(2x+5\right)\)

\(\Leftrightarrow65x-13x^2-10+2x=-54x-135\)

\(\Leftrightarrow-13x^2+121x+125=0\Leftrightarrow x=10,24...;x=-0,93...\)

\(\frac{2x-10}{6}=\frac{-27}{5-x}\)

\(\frac{2\left(x-5\right)}{6}=\frac{27}{x-5}\)

\(2\left(x-5\right)^2=27\times6\)

\(2x^2-20x+50-162=0\)

\(2x^2-20x-112=0\)

\(x^2-10x-56=0\)

\(x^2-14x+4x-56=0\)

\(\left(x-14\right)\left(x+4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-14=0\\x+4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=14\\x=-4\end{cases}}\)

KL .....

XIN TIICK

= 9 . \(\frac{1}{5}\) - 6 + 9 . \(\frac{4}{5}\)

= \(\frac{9}{5}\) - 6 + \(\frac{36}{5}\)

= 9 - 6

= 3

Học tốt

ta có \(z=\frac{1}{2}\left(\frac{a}{m}+\frac{b}{m}\right)=\frac{x+y}{2}\)

Vậy \(0< \frac{\left(y-x\right)}{2}=z-x\Rightarrow z>x\)

và \(z-y=\frac{x-y}{2}< 0\Rightarrow z< y\) vậy ta có đpcm

Ta có :

x < y hay a/m < b/m => a < b.

So sánh x ; y ; z ta chuyển chúng cùng mẫu : 2m

Mà : a < b

Suy ra : a + a < b + a

Hay : 2a < b + a

Suy ra : x < z ( 1 )

Hay a + b < 2b

Suy ra : x < y ( 2 )

1/144 nhé bạn.

Chúc bạn Ht

1/114 nha bn

#Hok tốt

\(\frac{x+3}{6}=\frac{2x+1}{7}\Rightarrow7x+21=12x+6\)

=> 12x - 7x = 21 - 6

=> 5x = 15

=> x = 3

\(\Rightarrow\frac{2.3+1}{7}=\frac{2+3.3}{y}\Rightarrow\frac{11}{y}=1\)

=> y = 11

Vậy, x = 3 và y = 11