-0-135= bao nhiêu mọi ngưới
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Bài 3:
\(2⋮n-1\Leftrightarrow n-1\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
ta có bảng:
n-1 | 1 | 2 | -1 | -2 |
n | 2 | 3 | 0 | -1 |
vậy......................
b)\(\frac{n+3}{n+1}=\frac{n+1+2}{n+1}=1+\frac{2}{n+1}\)
để \(\left(n+3\right)⋮\left(n+1\right)\Rightarrow2⋮n+1\Rightarrow n+1\inƯ\left(2\right)=\left\{\pm1\right\}\)
ta có bảng sau:
n+1 | 1 | 2 | -1 | -2 |
n | 0 | 1 | -2 | -3 |
\(P=\dfrac{x-1+9}{x-1}=1+\dfrac{9}{x-1}\Rightarrow x-1\inƯ\left(9\right)=\left\{\pm1;\pm3;\pm9\right\}\)
x-1 | 1 | -1 | 3 | -3 | 9 | -9 |
x | 2 | 0 | 4 | -2 | 10 | -8 |
\(\frac{6}{5}.x=\frac{7}{10}\)
\(x=\frac{7}{10}:\frac{6}{5}\)
\(x=\frac{7}{12}\)
a, \(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{-3}{6}+\frac{5}{6}+\frac{2}{6}=\frac{4}{6}=\frac{2}{3}\)
b, \(\frac{-3}{8}+\frac{7}{4}+\frac{1}{12}=\frac{-9}{24}+\frac{42}{24}+\frac{2}{24}=\frac{35}{24}\)
c, \(\frac{3}{5}:\left(\frac{1}{4}:\frac{7}{5}\right)=\frac{3}{5}:\frac{5}{28}=\frac{3}{5}.\frac{28}{5}=\frac{84}{25}\)
d, Ko rõ đề
e, \(\frac{5}{13}.\frac{8}{15}+\frac{5}{13}.\frac{26}{15}-\frac{5}{13}.\frac{8}{15}=\frac{5}{13}.\left(\frac{8}{15}+\frac{26}{15}-\frac{8}{15}\right)=\frac{5}{13}.\frac{13}{5}=1\)
#Fox
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
\(TH1:3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=\frac{1}{3}\)
\(TH2:\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(x=10\)
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
TH1:
\(3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=1\div3\)
\(x=\frac{1}{3}\)
TH2:
\(\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=0-5\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(\Leftrightarrow x=-5.\left(-2\right)\)
\(x=10\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=10\end{cases}}\)
a) \(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}.\)
b) \(\frac{-3}{8}+\frac{7}{4}+\frac{1}{12}=\frac{3}{8}+\frac{1}{12}=\frac{36}{96}+\frac{8}{96}=\frac{48}{96}=\frac{1}{2}\)
c) \(\frac{3}{5}\div\left(\frac{1}{4}\div\frac{7}{5}\right)=\frac{3}{5}\div\frac{5}{28}=\frac{3}{5}.\frac{28}{5}=\frac{84}{25}\)
d) \(\frac{10}{11}+\frac{4}{11}\div4-\frac{-1}{8}=\left(\frac{14}{11}\div4\right)-\frac{-1}{8}=\frac{7}{22}-\frac{1}{8}=\frac{56}{176}-\frac{22}{176}=\frac{34}{176}=\frac{17}{88}\)
e) \(\frac{5}{13}.\frac{8}{15}+\frac{5}{13}.\frac{26}{15}-\frac{5}{13}.\frac{8}{15}=\frac{5}{13}.\left(\frac{8}{15}+\frac{26}{15}-\frac{8}{15}\right)=\frac{5}{13}.\frac{26}{15}=\frac{130}{195}=\frac{26}{39}\)
135
HT
Âm 135 nha