Ex1

1 A

2 D

3 A

4 A

5 A

Ex2

1 A

2 A

3 A

3 C

4 A

Ex3

1 A

2 B

3 C

4 B

5 A

6 D

7 B

8 B

9 A

10 C

11 D

12 C

13 A

14 C

15 D

16 C

17 A

18 B

19 A

20 D

21 C

22 B

Prepare a map or we will be lost soon

A = - 5²² - { - 222 - [ - 122 - (100 - 5²²) + 2022] }

A = - 5²² - { -222 - [- 122 - 100 + 5²² ] + 2022}

A = - 5²² - { -222 - { - 222 + 5²² } + 2022}

A = - 5²² - {- 222 + 222 - 5²² + 2022}

A = -5²² + 5²² - 2022

A = - 2022

B = 1 + \(\dfrac{1}{2}\)(1 + 2) + \(\dfrac{1}{3}\).(1 + 2 + 3) + ... + \(\dfrac{1}{20}\).(1 + 2+ 3 + ... + 20)

B = 1+\(\dfrac{1}{2}\)\(\times\)(1+2)\(\times\)[(2-1):1+1]:2+ ... + \(\dfrac{1}{20}\)\(\times\) (20 + 1)\(\times\)[(20-1):1+1]:2

B = 1 + \(\dfrac{1}{2}\) \(\times\) 3 \(\times\) 2:2 + \(\dfrac{1}{3}\) \(\times\)4 \(\times\) 3 : 2+....+ \(\dfrac{1}{20}\) \(\times\)21 \(\times\) 20 : 2

B = 1 + \(\dfrac{3}{2}\) + \(\dfrac{4}{2}\) + ....+ \(\dfrac{21}{2}\)

B = \(\dfrac{2+3+4+...+21}{2}\)

B = \(\dfrac{\left(21+2\right)\left[\left(21-2\right):1+1\right]:2}{2}\)

B = \(\dfrac{23\times20:2}{2}\)

B = \(\dfrac{23\times10}{2}\)

B = 23 

(2n + 28) ⋮ (n + 3)    (n \(\ne\) -3)

(2n + 6 + 22) ⋮ (n + 3)

[2.(n + 3) + 22]⋮ (n + 3)

                 22  ⋮ (n + 30

(n + 3) \(\in\)  Ư(22) 

22 = 2.11 ⇒ Ư(22) = {-22; -11; -2; -1; 1; 2; 11; 22}

Lập bảng ta có:

Theo bảng trên ta có: 

n \(\in\) {-25; -14; -5; -4; -2; -1; 8; 19}

1 interesting

2 natural

3 well

4 discussion

5 chilhood

6 dangerous

7 information

8 tourist

9 comfortable 

10 cheaper

cảm ơn ạ

Ex8

1 than

2 than

3 as

4 as

5 as

6 than

7 than

8 as

Ex9

2 A mile is farther than a kilometer

3 The sky blue is paler than a navy blue

4 A dolphin is cleverer than a snake

5 Gold is more valuable than silver

6 Yoga is more relaxing than football

7 Wind energy is cleaner than nuclear energy

8 A billionaire is richer than a millionaire

Ex10

1 from

2 peaceful

3 flowers

4 for

5 however

6 carpet

7 often

8 warer

9 path

10 fresh

Ex11

1 interesting

2 natural

3 well

4 discussion

5 childhood

6 dangerous

7 information

8 tourist

9 comfortable 

10 cheaper 

a/

2020.2021=(2019+1)(2022-1)=

=2019.2022-2019+2022-1=2019.2022+2>2019.2022

b/

\(4^7=\left(2^2\right)^7=2^{14}< 2^{15}\)

c/

\(199^{20}< 200^{20}=\left(8.25\right)^{20}=\left(2^3.5^2\right)^{20}=2^{60}.5^{40}\)

\(2000^{15}=\left(16.125\right)^{15}=\left(2^4.5^3\right)^{15}=2^{60}.5^{45}\)

\(\Rightarrow2000^{15}=2^{60}.5^{45}>2^{60}.5^{40}>199^{20}\)

d/

\(31^{31}< 32^{31}=\left(2^5\right)^{31}=2^{155}\)

\(17^{39}>16^{39}=\left(2^4\right)^{39}=2^{156}\)

\(\Rightarrow17^{39}=2^{156}>2^{155}>31^{31}\)

Ex6

1 to eat

2 any

3 to do

4 is going to visit

5 is driving

6 must

7 much

8 going

9 a

10 to have

11 many

12 dozen

63 ⋮ \(x\); 2970 ⋮ \(x\) ⇒ \(x\) \(\in\) ƯC(63; 2970) 

63 =7.3²; 2970 = 2.3².5.11 ⇒ ƯCLN(63; 2970) = 3² = 9

⇒ \(x\)  \(\in\) Ư(9)

9 = 3² ⇒ Ư(9) = {-9;  - 3; -1; 1; 3; 9}

⇒ \(x\) \(\in\) {-9; -3; -1; 1; 3; 9}