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Chứng minh tam giác NCM và tam giác MBA

Trả lời:

\(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=\frac{2}{5}\\x+\frac{1}{2}=-\frac{2}{5}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{10}\\x=-\frac{9}{10}\end{cases}}\)

https://lazi.vn/users/dang_ky?u=kieu-anh.pham4

Trả lời:

\(\frac{4^6.9^9+6^9.102}{8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^6+\left(2.3\right)^9.2.3.17}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2^{12}.3^{12}+2^9.3^9.2.3.17}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{12}+2^{10}.3^{10}.17}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{10}.3^{10}.\left(2^2.3^2+17\right)}{2^{10}.3^{10}.\left(2^2.3^2-2.3\right)}=\frac{2^2.3^2+17}{2^2.3^2-2.3}=\frac{53}{30}\)

\(3x+\frac{2}{2}x-1=5\)

\(\Rightarrow x\left(3+\frac{2}{2}\right)=5+1=6\) \(\Rightarrow4x=6\) \(\Rightarrow x=\frac{6}{4}=\frac{3}{2}=1,5\)

~~ HT ~~

\(3x+\frac{2}{2}\)\(x-1=5\)

\(\left(3+\frac{2}{2}\right)x=5+1\)

\(\left(3+\frac{2}{2}\right)x=6\)

\(\left(3+1\right)x=6\)

\(4x=6\)

\(x=\frac{6}{4}\)\(x=1,5\)

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