Nếu x < 1 => |-x + 1| = -x + 1

|2x - 3| = -(2x - 3) = -2x + 3

Khi đó B = |-x + 1| + |2x - 3| - 2(x - 1)

= -x + 1 - 2x + 3 - 2x + 2

= - 5x + 6

Nếu \(1\le x\le1,5\)

=> |-x + 1| = x - 1 

 |2x - 3| = --2x + 3

Khi đó B = x - 1 - 2x + 3 - 2x + 2

= -4x + 4

Nếu x > 1,5 => |-x + 1| = x - 1

|2x - 3| = 2x - 3

Khi đó B = x - 1 + 2x - 3 -2x + 2 

= x - 2 

how to đăng bài?

please help me

bạn chép cả đề bài ra đi mình giải cho

Chứng minh tam giác NCM và tam giác MBA

Trả lời:

\(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=\frac{2}{5}\\x+\frac{1}{2}=-\frac{2}{5}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{10}\\x=-\frac{9}{10}\end{cases}}\)

https://lazi.vn/users/dang_ky?u=kieu-anh.pham4

Trả lời:

\(\frac{4^6.9^9+6^9.102}{8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^6+\left(2.3\right)^9.2.3.17}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2^{12}.3^{12}+2^9.3^9.2.3.17}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{12}+2^{10}.3^{10}.17}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{10}.3^{10}.\left(2^2.3^2+17\right)}{2^{10}.3^{10}.\left(2^2.3^2-2.3\right)}=\frac{2^2.3^2+17}{2^2.3^2-2.3}=\frac{53}{30}\)