3 + 32 + 33 + 34 ⋮ 4
2 + 22 + 23 + ... + 22020 + 22021 + 22022 ⋮ 3
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\(S=2+2^2+2^3+...+2^{10}\)
\(S=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^9+2^{10}\right)\) (5 cặp )
\(S=2\left(1+2\right)+2^3\left(1+2\right)+..+2^9\left(1+2\right)\)
\(S=2\cdot3+2^3\cdot3+...+2^9\cdot3\)
\(=3\left(2+2^3+..+2^9\right)⋮3\left(dpcm\right)\)
`5^3 - 5.(4+x)=15`
`5.(4+x)=5^3-15`
`5.(4+x)=125-15`
`5.(4+x)=110`
`4+x=110:5`
`4+x=22`
`x=22-4`
`x=18`
Vậy `x=18`
53 - 5 ( 4 + x ) = 15
= 125 - 5 ( 4 + x ) = 15
= 5 ( 4 + x ) = 125 - 15
= 5 ( 4 + x ) = 110
= 4+x = 110:5
= 4 + x = 22
= x = 22 - 4
= x = 18
a, 6.3.9.2.18 = (6.3).(9.2).18 = 18.18.18 = 183
2.4.8.16.4 = (8.2).(4.4).16 = 16.16.16 = 163
c, 7.7.7.7.7 = 75
d, 103. 102 . 10 = 103 + 2 + 1 = 106
a, 6.3.9.2.18 = (6.3).(9.2).18 = 18.18.18 = 183
2.4.8.16.4 = (8.2).(4.4).16 = 16.16.16 = 163
c, 7.7.7.7.7 = 75
d, 103. 102 . 10 = 103 + 2 + 1 = 106
2 mu~ 2 =2 x 2 = 4
3 mu~ 2 = 3 x 3 = 9
4 mu~ 2 = 4 x 4 = 16
5 mu~ 2 = 5 x 5 = 25
6 mu~ 2 = 6 x 6 = 36
7 mu~ 2 = 7 x 7 = 14
8 mu~ 2 = 8 x 8 = 16
9 mu~ 2 = 9 x 9 = 81
10 mu~ 2 = 10 x 10 = 100
\(3+3^2+3^3+3^4\)
\(=3\left(1+3+3^2+3^3\right)\)
\(=3\cdot40\)
\(=3\cdot10\cdot4⋮4\left(dpcm\right)\)
\(2+2^2+2^3+....+2^{2022}\)
\(=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{2021}+2^{2022}\right)\)
\(=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{2021}\left(1+2\right)\)
\(=2\cdot3+2^3\cdot3+...+2^{2021}\cdot3\)
\(=3\left(2+2^3+...+2^{2011}\right)⋮3\left(dpcm\right)\)