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Đề thi đánh giá năng lực
\(=\frac{15}{16}-log_a\left[\left(\left(a^{\frac{1}{4}}\right)^{\frac{1}{4}}\right)^{10+1}\right]\)
\(=\frac{15}{16}-log_aa^{\frac{11}{16}}=\frac{15}{16}-\frac{11}{16}=\frac{1}{4}\)
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tính E(300)=300/log2(300), E(90000)=90000/log2(90000)
Vì độ hiệu quả tỉ lệ thuận với thời gian thực hiện
nên ta có tỉ số 0,02/E(300)=x/E(90000) (x là giá trị cần tìm).
Từ đó tính được x=3