Tìm x biết a) \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}...\frac{30}{62}.\frac{31}{64}=2^x\) b) \(9^{2x-1}=\frac{1}{3}\) c) \(3.8^x-2.2^{3x}-16=0\)
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\(\frac{3}{14}:\frac{1}{28}-\frac{13}{21}:\frac{1}{28}+\frac{29}{42}:\frac{1}{28}-8\)
\(=\left(\frac{3}{14}-\frac{13}{21}+\frac{29}{42}\right):\frac{1}{28}-8\)
\(=\left(\frac{9}{42}-\frac{26}{21}+\frac{29}{42}\right):\frac{1}{28}-8\)
\(=\left(\frac{-17}{42}+\frac{29}{42}\right):\frac{1}{28}-8\)
\(=\frac{12}{42}:\frac{1}{28}-8\)
\(=\frac{2}{7}.28-8\)
\(=\frac{56}{7}-8\)
\(=8-8\)
\(=0\)
D = -1-1/3-1/6-1/10-...-1/1225
Suy ra : D/2=-1/2-1/6-1/12-....-1/2450
Mà 1/2=1/(1.2)=1-1/2; 1/6=1/(2.3)=1/2-1/3;...1/2450=1/(49.50)=...
D/2= -(1-1/2)-(-1/2-1/3)-...-(1/49-1/50)
D/2= -1+1/2-1/2+1/3-....-1/49+1/50
D/2= -1+1/50=-49/50
D=(-49/50).2=-98/50
k nha
a)Vì x^2 >=0 ; x^4>= 0
=> A = x^4 + 3x^2 - 4 >= -4
Vậy min A = -4 tại x = 0
b) x^2 >= 0 với mọi x
=> B = ( x^2 + 5 )^2 + 4 >= ( 0 + 5 )^2 + 4 = 29
Vậy Min B = 29 tại x = 0
a. \(\Rightarrow\frac{1.2.3.4.5....30.31}{4.6.8.10.12....62.64}=2^x\)
\(\Rightarrow\frac{1.2.3.4.5....30.31}{2.2.3.2.4.2.5.2.6.2....31.2.64}=2^x\)
\(\Rightarrow\frac{1}{2.2.2.2....2.2\left(\text{30 số 2}\right).64}=2^x\)
\(\Rightarrow\frac{1}{2^{30}.2^6}=2^x\)
\(\Rightarrow\frac{1}{2^{36}}=2^x\)
\(\Rightarrow2^{-36}=2^x\)
Vậy \(x=-36\).
b.\(9^{2x-1}=\frac{1}{3}\)
\(\Rightarrow\left(3^2\right)^{2x-1}=\frac{1}{3}\)
\(\Rightarrow3^{2.\left(2x-1\right)}=\frac{1}{3}\)
\(\Rightarrow3^{4x-2}=\frac{1}{3}\)
\(\Rightarrow3^{4x-2}=3^{-1}\)
\(\Rightarrow4x-2=-1\)
=> 4x=-1+2
=> 4x=1
Vậy x =\(\frac{1}{4}\)
c.\(3.8^x-2.2^{3x}-16=0\)
\(\Rightarrow3.\left(2^3\right)^x-2.2^{3x}-16=0\)
\(\Rightarrow3.2^{3x}-2.2^{3x}-16=0\)
\(\Rightarrow2^{3x}.\left(3-2\right)-16=0\)
\(\Rightarrow2^{3x}.1-16=0\)
\(\Rightarrow2^{3x}=16\)
\(\Rightarrow2^{3x}=2^4\)
=> 3x=4
Vậy x=\(\frac{4}{3}\)