Tả cây phượng vĩ và tiếng ve ngày hè .
tự làm nhé, ai chép mạng mình sẽ báo cáo vi phạm, ai tự làm mình tick
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meaning to Complete the second sentence so that it has simila the first sentence.
1.the Blue Hotel is cheaper than the Green Hotel
2. the square in Hoi An is smaller than the square in Ha Noi
3. Should we go out and have an ice cream?
4.what is the way to the bus stop ?
5. our neighbourhood is more peachful than your neighbourhood .
có j sai xin thứ lỗi nha, còn nếu đúng cho mik xin
1. The Green Hotel is more expensive than the Blue Hotel.
---> The Blue Hotel is cheaper than the Green Hotel
2. The square in Ha Noi is bigger/ larger than the square in Hoi An
---> The square in Hoi An is smaller than the square in Ha Noi
3. Shall we go out and have an ice cream?
---> Should we go out and have an ice cream ?
4. How can we go/ get to the bus stop?
---> What way we can go to the bus stop ?
5. Your neighbourhood is noisier than our neighbourhood
---> Our neighbourhood is quieter than your neighbourhood.
Đèn điện, xe cộ, cây cối, tòa nhà, các công ty,những quán ăn vỉa hè,...
Học tốt. xin cái
a) x - 920 = 99920
x = 99920 + 920
x = 100840
b) x + 90 - (-29) = 10020
x + 90 = 10020 + (-21)
x + 90 = 9991
x = 9991 - 90
x = 9901
c) 99 - x = 90
x = 99 - 90
x = 9
d) -x + 93 = -1
-x = -1 - 93
-x = -94
a, x - 920 = 99920 c, 99 - x = 90
x = 99920 + 920 x = 99 - 90
x = 100840 x = 9
Vậy x = 100840 Vậy x = 9
b,x + 90 - (-29) = 100020
x + 90 = 100020 + ( -29 )
x + 90 = 99991
x = 99991 - 90
x = 99901
Vậy x = 99901
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Ta có : \(3.2^x=2^8+2^9\)
\(\Rightarrow3.2^x=2^8.\left(1+2\right)\)
\(\Rightarrow3.2^x=2^8.3\)
\(\Rightarrow2^x=2^8\)
\(\Rightarrow x=8\)
Vậy \(x=8\)
Sửa đề:
\(E=\frac{1}{1.101}+\frac{1}{2.102}+\frac{1}{3.103}+...+\frac{1}{10.110}\)
=> \(100.E=\frac{100}{1.101}+\frac{100}{2.102}+\frac{100}{3.103}+...+\frac{100}{10.110}\)
\(=\frac{101-1}{1.101}+\frac{102-2}{2.102}+\frac{103-3}{3.103}+...+\frac{110-10}{10.110}\)
\(=1-\frac{1}{101}+\frac{1}{2}-\frac{1}{102}+\frac{1}{3}-\frac{1}{103}+...+\frac{1}{10}-\frac{1}{110}\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)-\left(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{110}\right)\)
\(F=\frac{1}{1.11}+\frac{1}{2.12}+\frac{1}{3.13}+...+\frac{1}{100.110}\)
=> \(10F=\frac{10}{1.11}+\frac{10}{2.12}+\frac{10}{3.13}+...+\frac{10}{100.110}\)
\(=\frac{11-1}{1.11}+\frac{12-2}{2.12}+\frac{13-3}{3.13}+...+\frac{110-100}{100.110}\)
\(=1-\frac{1}{11}+\frac{1}{2}-\frac{1}{12}+\frac{1}{3}-\frac{1}{13}+...+\frac{1}{100}-\frac{1}{110}\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)+\left(-\frac{1}{11}+\frac{1}{11}\right)+\left(-\frac{1}{12}+\frac{1}{12}\right)+...+\left(-\frac{1}{100}+\frac{1}{100}\right)\)
\(-\left(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{110}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)-\left(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{110}\right)=100E\)
=> 10 F = 100 E
=> \(\frac{E}{F}=\frac{10}{100}=\frac{1}{10}\)