Vì \(\hept{\begin{cases}\left|x-2\right|\ge0\\\sqrt{\left(y+1\right)^{2015}}\ge0\end{cases}\Rightarrow\left|x-2\right|+\sqrt{\left(y+1\right)^{2015}}\ge}0\)

Dấu "=" của đẳng thức xảy ra khi \(\left|x-2\right|=\sqrt{\left(y+1\right)^{2015}}=0\)

\(\left|x-2\right|=0\Leftrightarrow x-2=0\Leftrightarrow x=2\)

\(\sqrt{\left(y+1\right)^{2015}}=0\Leftrightarrow\left(y+1\right)^{2015}=0\Leftrightarrow y+1=0\Leftrightarrow y=-1\)

Thay x=2 và y=-1 vào biểu thức P ta có:

\(P=2x^3+15y^3+2016=2.2^3+15.\left(-1\right)^3+2016=16+\left(-15\right)+2016=2017\)

Vậy ................

\(P=2.2^3-15+2016=2017\)

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= 1965,6 thì phải

a) Xét tam giác ABC vuông tại A có:

      \(AB^2+AC^2=BC^2\left(pytago\right)\)

      \(8^2+6^2=BC^2\left(64+36=100\right)\)

   \(\Rightarrow BC=\sqrt{100}=10cm\)

b) Câu này viết lại đề đi

Ta có: \(\left(-32\right)^{27}=\left(-2^5\right)^{27}=\left(-2\right)^{135}\)

\(Mà:\left(-18\right)^{19}< \left(-16\right)^{19}=\left(-2^4\right)^{39}=\left(-2\right)^{136}< \left(-2\right)^{135}=\left(-32\right)^{27}\)

\(\Rightarrow\left(-18\right)^{39}< \left(-32\right)^{27}\)

(-18)^339>(-32)^27

tk minh nha

tỉ lệ thuận

tỉ lệ nghịch

Số thứ 17 là:

    7 - 6 = 1

      Đ/s:..

tổng của mười sáu số là : 

   6 x 16 = 96

tổng của mười bảy số là :

    7 x 17 = 119

số thứ mười bảy là :

  119 - 96 = 23

       đáp số : 23