\(\frac{2}{4}\)=\(\frac{1}{2}\)=\(\frac{-y}{3}\)
Tìm y thuộc Z biết
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Trả lời :
Ta có :
\(\frac{x}{4}=\frac{1}{2}\Rightarrow2x=4\Rightarrow x=2\)
\(\frac{1}{2}=\frac{-y}{3}\Rightarrow2y=-3\Rightarrow y=\frac{-3}{2}\)
\(\frac{x}{4}=\frac{1}{2}=\frac{-y}{3}\)
* \(\frac{x}{4}=\frac{1}{2}\Rightarrow2x=4\Rightarrow x=2\)
* \(\frac{1}{2}=\frac{-y}{3}\Rightarrow3=-2y\Rightarrow y=-\frac{3}{2}\)
Bài làm:
a) Ta có: \(\hept{\begin{cases}4n-1⋮n-1\\n-1⋮n-1\end{cases}\Rightarrow\hept{\begin{cases}4n-1⋮n-1\\4n-4⋮n-1\end{cases}}}\)
\(\Rightarrow4n-1-\left(4n-4\right)⋮n-1\)
\(\Rightarrow3⋮n-1\)
\(\Rightarrow n-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
\(\Rightarrow n\in\left\{-2;0;2;4\right\}\)
Vậy \(n\in\left\{-2;0;2;4\right\}\)
b) Ta có: \(\hept{\begin{cases}n-1⋮n^2-2\\n^2-2⋮n^2-2\end{cases}\Rightarrow\hept{\begin{cases}n^2-n⋮n^2-2\\n^2-2⋮n^2-2\end{cases}}}\)
\(\Rightarrow n^2-2-\left(n^2-n\right)⋮n^2-2\)
\(\Rightarrow n-2⋮n^2-2\), mà ta có \(n-1⋮n^2-2\)
\(\Rightarrow n-1-\left(n-2\right)⋮n^2-2\)
\(\Rightarrow1⋮n^2-2\)
\(\Leftrightarrow n^2-2\inƯ\left(1\right)=\left\{-1;1\right\}\)
\(\Leftrightarrow n^2\in\left\{1;3\right\}\)
Mà nếu n2 = 3 thì n không là số nguyên
\(\Rightarrow n^2=1\Leftrightarrow\orbr{\begin{cases}n=1\\n=-1\end{cases}}\)
Vậy \(\orbr{\begin{cases}n=1\\n=-1\end{cases}}\)
Học tốt!!!!
1).......to Ho Chi Minh city next week.
2)........to shopping mall last night.
2 câu còn lại hổng biết
1. ___Where is he going to visit next week?
___When is he going to visit Ho Chi Minh City?
2. ___Where did they go last night?
___When did they go to the shopping mall?
3. ___What is the most expensive house in the town?
4. ___Where did he travelled by plane?