3 mũ 1001 (5+2x) = 3 mũ 999
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)
\(3^{21}-3^{18}\\ =3^{17}.\left(3^4-3\right)\\ =3^{17}.\left(81-3\right)\\ =3^{17}.78\)
Vì \(3^{17}.78⋮78\) nên \(3^{21}-3^{18}⋮78\) (đpcm)
Vậy...
b)
\(81^7-27^9-9^{13}\\
=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\\
=3^{28}-3^{27}-3^{26}\\
=3^{24}.\left(3^4-3^3-3^2\right)\\
=3^{24}.\left(81-27-9\right)\\
=3^{24}.45\)
Vì \(3^{24}.45⋮45\) nên \(81^7-27^9-9^{13}⋮45\) (đpcm)
Vậy...
\(2^{n+1}=2^3\)
\(\Rightarrow n+1=3\)
\(\Rightarrow n=3-1\)
\(\Rightarrow n=2\)
Vậy: n=2
\(\dfrac{7}{5}.x+\dfrac{4}{5}=\dfrac{-7}{10}\)
\(=>\dfrac{7}{5}.x=\dfrac{-7}{10}-\dfrac{4}{5}=\dfrac{-7}{10}-\dfrac{8}{10}\)
\(=>\dfrac{7}{5}.x=-\dfrac{15}{10}\)
\(=>x=\dfrac{-15}{10}:\dfrac{7}{5}=\dfrac{-15}{10}.\dfrac{5}{7}\)
\(=>x=\dfrac{-15}{14}\)
`#3107.101107`
\(\dfrac{1}{4}\times x+\dfrac{4}{5}=-\dfrac{7}{10}\)
\(\Rightarrow\dfrac{1}{4}\times x=-\dfrac{7}{10}-\dfrac{4}{5}\)
\(\Rightarrow\dfrac{1}{4}\times x=-\dfrac{3}{2}\)
\(\Rightarrow x=-\dfrac{3}{2}\div\dfrac{1}{4}\)
\(\Rightarrow x=-6\)
Vậy, `x = -6.`
1/4 . x + 4/5 = -7/10
1/4 . x = -7/10 - 4/5
1/4 . x = -3/2
x = -3/2 : 1/4
x = -6
\(3^{1001}\cdot\left(5+2x\right)=3^{999}\)
\(\Rightarrow5+2x=\dfrac{3^{999}}{3^{1001}}\)
\(\Rightarrow5+2x=\dfrac{1}{3^2}\)
\(\Rightarrow5+2x=\dfrac{1}{9}\)
\(\Rightarrow2x=\dfrac{1}{9}-5\)
\(\Rightarrow2x=-\dfrac{44}{9}\)
\(\Rightarrow x=-\dfrac{44}{9}:2\)
\(\Rightarrow x=-\dfrac{22}{9}\)
\(3^{1001}.\left(5+2x\right)=3^{999}\)
\(\Rightarrow5+2x=\dfrac{3^{999}}{3^{1001}}\)
\(\Rightarrow5+2x=\dfrac{1}{3^2}\)
\(\Rightarrow5+2x=\dfrac{1}{9}\)
\(2x=\dfrac{1}{9}-5\)
\(x=-\dfrac{44}{9}:2\)
\(x=-\dfrac{22}{9}\)