\(\dfrac{9}{21}+\dfrac{6}{49}=\dfrac{3}{7}+\dfrac{6}{49}=\dfrac{21}{49}+\dfrac{6}{49}=\dfrac{27}{49}\)

b: \(\dfrac{101}{103}=1-\dfrac{2}{103}\)

\(\dfrac{11}{13}=1-\dfrac{2}{13}\)

\(\dfrac{2009}{2011}=1-\dfrac{2}{2011}\)

\(\dfrac{69}{71}=1-\dfrac{2}{71}\)

Vì 13<71<103<2011

nên \(\dfrac{2}{13}>\dfrac{2}{71}>\dfrac{2}{103}>\dfrac{2}{2011}\)

=>\(-\dfrac{2}{13}< -\dfrac{2}{71}< -\dfrac{2}{103}< -\dfrac{2}{2011}\)

=>\(-\dfrac{2}{13}+1< -\dfrac{2}{71}+1< -\dfrac{2}{103}+1< -\dfrac{2}{2011}+1\)

=>\(\dfrac{11}{13}< \dfrac{69}{71}< \dfrac{101}{103}< \dfrac{2009}{2011}\)

a: \(\dfrac{17}{13}=1+\dfrac{4}{13};\dfrac{61}{57}=1+\dfrac{4}{57}\)

\(\dfrac{2012}{2009}=1+\dfrac{3}{2009};\dfrac{123}{120}=1+\dfrac{3}{120}\)

Vì \(\dfrac{3}{2009}< \dfrac{3}{120}\left(2009>120\right);\dfrac{3}{120}< \dfrac{4}{57};\dfrac{4}{57}< \dfrac{4}{13}\left(57>13\right)\)

nên \(\dfrac{2012}{2009}< \dfrac{123}{120}< \dfrac{61}{57}< \dfrac{17}{13}\)

câu a

\(\dfrac{2012}{2009}< \dfrac{123}{120}< \dfrac{61}{57}< \dfrac{17}{13}\)

câu b

\(\dfrac{11}{13}< \dfrac{69}{71}< \dfrac{101}{103}< \dfrac{2009}{2011}\)

Vận tốc trung bình là:

\(\dfrac{15+10}{2}=12,5\left(\dfrac{km}{h}\right)\)

vận tốc trung bình của người đó trên quãng đường AB là:

(15 + 10) : 2 = 12,5 (km/h)

đáp số: 12,5 km/h

Giả sử x+y=0

=>x=-y

\(\left(\sqrt{x^2+3}+x\right)\left(\sqrt{y^2+3}+y\right)\)

\(=\left(\sqrt{\left(-y\right)^2+3}-y\right)\left(\sqrt{y^2+3}+y\right)\)

\(=\left(\sqrt{y^2+3}-y\right)\left(\sqrt{y^2+3}+y\right)\)

\(=y^2+3-y^2=3\)(Đúng với Giả thiết)

=>ĐPCM

minh cam on cau 

`16/2^x = 2`

`=>2^x=16/2`

`=>2^x=4`

`=>2^x=2^2`

`=>x=2`

Vậy x=2

a: \(5871:\left[928-\left(247-82\cdot5\right)\right]\)

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left[928-247+410\right]\)

\(=5871:1091=\dfrac{5871}{1091}\)

d: \(777:7+1331:11^3\)

=111+1

=112

1 câu thui

Bài 5:

a: 12+89+23+45+55+11+77+88

=(12+88)+(89+11)+(23+77)+(45+55)

=100+100+100+100

=400

b: 2x4+2x5+2

=2x(4+5+1)

=2x10=20

Bài 4:

405cm=4m5cm

1210mm=1m10mm

8m5dm=85dm

12cm7mm=127mm

Bài 3:

5m=5000mm

2000m=2km

200cm=2m

72cm=720mm

801m=8010dm

800cm=8m

Bài 1:

a: Số thứ nhất là số lẻ bé nhất có 1 chữ số

=>Số thứ nhất là 1

Số thứ hai là 18-1=17

b: Hiệu là 17-1=16

\(100:\left\{250:\left[450-\left(4\cdot5^3-2^2\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(4\cdot125-4\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(500-100\right)\right]\right\}\)

\(=100:\left\{250:\left[450-400\right]\right\}\)

\(=100:\left\{250:50\right\}=100:5=20\)

\(100:\left\{250:\left[450-\left(4\cdot5^3-2^2\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(4\cdot125-4\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(500-100\right)\right]\right\}\)

\(=100:\left[250:\left(450-400\right)\right]\)

\(=100:\left(250:50\right)\)

\(=100:5\)

\(=20\)