a, 3x² - 3x ( x - 2 ) = 36

     3x² - 3x² + 6x   = 36

               6x = 36 

          => x=6

\(\Rightarrow x^2+2xy+y^2+y^2-2y+1=0\)

\(\Rightarrow\left(x+y\right)^2+\left(y-1\right)^2=0\)

\(\Rightarrow\hept{\begin{cases}x+y=0\\y-1=0\end{cases}\Rightarrow\hept{\begin{cases}x=-y\\y=1\end{cases}\Rightarrow}\hept{\begin{cases}x=-1\\y=1\end{cases}}}\)

\(\left(x^2+1\right)^2-4x^2=\left(x^2+1\right)^2-\left(2x\right)^2=\left(x^2+1-2x\right)\left(x^2+1+2x\right)=\left(x-1\right)^2\left(x-1\right)^2\)

(x²+1)² - 4x²

=(x²+1)² - (2x)²

=(x²+1-2x)(x²+1+2x)

=(x²-2x+1)(x²+2x+1)

=(x-1)²(x+1)²

ta có : \(3n^3+10n^2-5⋮3n+1\)

\(\Rightarrow3n^3+n^2+9n^2+3n-3n-1-4⋮3n+1\)

\(\Rightarrow n\left(3n+1\right)+3n\left(3n+1\right)-\left(3n+1\right)-3⋮3n+1\)

\(\Rightarrow\left(n+3n+1\right)\left(3n+1\right)-4⋮3n+1\)

mà \(\left(4n+1\right)\left(3n+1\right)⋮3n+1\)

\(\Rightarrow3n+1\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)

\(\Rightarrow n\in\left\{0;\pm1\right\}\)

Đa thức (3x⁵  -8x³ - x² ) : (-3xⁿ)

Khi 3x⁵ : (-3xⁿ)    => n \(\le\)5

      8x^{5 :} (-3xⁿ)    => n\(\le\)3

      x² : (-3xⁿ)     => n\(\le\)2

Suy ra n\(\le\)2

Vậy n \(\le\)2  thì phép chia đó là phép chia hết

=2022 nhoa 

Sam k Min nhoa

Yew Sam!

= 2022

k nha e

#Huy#