\(2\left|2y+4\right|\ge0;\left|-1\right|=1\Rightarrow2\left|2y+4\right|+\left|-1\right|>0\)

Mà \(2\left|2y+4\right|+\left|-1\right|=0\) ( vô lý )

Vậy không tồn tại y thỏa mãn nên không xác định A

Tần số = 30

Số tuổi nghề = 6

Ta có : \(\overline{x}=6,\left(63\right)=\frac{663-6}{99}=\frac{657}{99}=\frac{73}{11}\)

=> \(\frac{5\cdot n+6\cdot5+9\cdot2+10\cdot1}{n+5+2+1}=\frac{73}{11}\)

=> \(\frac{5n+30+18+10}{n+8}=\frac{73}{11}\)

=>\(\frac{5n+58}{n+8}=\frac{73}{11}\)

=> \(11\left(5n+58\right)=73\left(n+8\right)\)

=> \(55n+638=73n+584\)

=> \(18n=54\)

=> \(n=3\)

Vậy n = 3

có ai giúp với

\(\text{Đặt x=4y}=\frac{z-9}{125}=k\)

\(\Leftrightarrow\hept{\begin{cases}x=k\\y=\frac{1}{4}k\\z=125k+9\end{cases}}\)

\(\Rightarrow\frac{505}{4}k=2029\)

\(\text{Mà x+y+z=2029}\)

\(\Rightarrow k+\frac{1}{4}k+125k+9=2029\)

\(\Rightarrow\frac{505}{4}k=2020\Rightarrow k=16\)

\(\Rightarrow\hept{\begin{cases}x=16\\y=4\\z=2009\end{cases}}\)

\(\frac{7.2^{32}.3^8.5^4-2^9.3^9.2^8.5^4}{2^{10}.3^{10}.2^5.5^5-7.3^9.4^8.5^4}=\frac{7.2^{32}.3^8.5^4-2^{17}.3^9.5^4}{2^{15}.3^{10}.5^5-7.3^9.2^{16}.5^4}\)

\(\frac{2^{17}.3^8.5^4\left(2^5.7-1\right)}{2^{15}.3^9.5^4\left(3.5-7.2\right)}=\frac{2^{17}.3^8.5^4\left(32.7-1\right)}{2^{15}.3^9.5^4\left(15-14\right)}\)