tìm x,y:(2x-1)^2014+(x-y-1/2)^2016=0
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Ann lives in London. She is twenty nine and works (1) _works_____ the BBC. She interviews people on an early morning news program called The World Today. Every weekday she (2) ___gets____ up at 3 in the morning because the program starts at 6.30. She loves (3) __her______ work because it is exciting and she meets a lot of interesting people, and she loves her weekends, (4) ___too_______
On Fridays, she comes (5) __home______from the BBC at about 2 in the afternoon and she just relax. On Friday evenings she doesn’t go out, but sometimes a friends comes for (6) _dinner_____ He or she brings wine and they cook. Ann (7) ___loves___ cooking. They listen to music or just chat.
On Saturday mornings she gets up at 9 and she goes shopping. Then in the evening she sometimes goes to the theater or the opera (8) __with_______a friend – she loves opera. Then they eat in her favorite Chinese restaurant. On Sunday morning she stays in bed late. She doesn’t get up (9) __until______ 11 o’clock. Sometimes in the afternoon, she visits her sister. She lives in the country and has two (10) __children_______. She s playing with her niece and nephew, but she leaves early because she goes to bed at 8 on Sunday evenings..
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https://olm.vn/hoi-dap/detail/78501273833.html
tham khaor
Tham khaorlink này nek:
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Xet \(M-1=a+\frac{2a+2}{2-b}-\left(\frac{2a-b}{2+b}+1\right)+\frac{4a}{b^2-4}\)
=\(a+\left(2a+2\right)\left(\frac{1}{2-b}-\frac{1}{2+b}\right)+\frac{4a}{b^2-4}\)
=\(\frac{ab^2-4a-4ab-4b+4a}{b^2-4}\)
=\(\frac{ab^2-4ab-4b}{b^2-4}\)
den doan nay em xet rieng tu so \(ab^2-4ab-4b\)
thay b=a/a+1 vao \(\frac{a^3}{\left(a+1\right)^2}-\frac{4a^2}{a+1}-\frac{4}{a+1}\)
=\(\frac{a\left(a+2\right)\left(-3a-2\right)}{\left(a+1\right)^2}\)
xet mau so b^2-4=(a/a+1)^-4
=\(\frac{\left(a+2\right)\left(-3a-2\right)}{\left(a+1\right)^2}\)
den day thay vao la xong nha
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2. Câu hỏi của Đình Hiếu - Toán lớp 7 - Học toán với OnlineMath
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link hơi dài nhưng bn tham khảo nha:
https://lazi.vn/edu/exercise/cho-oz-la-tia-phan-giac-cua-goc-xoy-co-so-do-la-60-do-tu-b-thuoc-ox-ve-duong-thang-song-song-voi-oy
Đề bài ? Tìm x,y à
Ta có : \(\left(2x-1\right)^{2014}\) \( \geq\) \(0\) với mọi x
\(\left(x-y-\frac{1}{2}\right)^{2016}\) \( \geq\) \(0\) với mọi x ; y
\(\implies\)\(\left(2x-1\right)^{2014}+\left(x-y-\frac{1}{2}\right)^{2016}\) \( \geq\) \(0\) với mọi x ; y
Mà \(\left(2x-1\right)^{2014}+\left(x-y-\frac{1}{2}\right)^{2016}=0\)
\(\implies\) Dấu bằng xảy ra \(\iff\) \(\hept{\begin{cases}\left(2x-1\right)^{2014}=0\\\left(x-y-\frac{1}{2}\right)^{2016}=0\end{cases}}\) \(\iff\) \(\hept{\begin{cases}2x-1=0\\x-y-\frac{1}{2}=0\end{cases}}\) \(\iff\) \(\hept{\begin{cases}x=\frac{1}{2}\\y=0\end{cases}}\)