\(\frac{5}{2x-4}=\frac{5}{2\left(x-2\right)}\)( ĐKXĐ : x ≠ 2 )

\(\frac{4}{3x-9}=\frac{4}{3\left(x-3\right)}\)( ĐKXĐ : x ≠ 3 )

\(\frac{7}{50-25x}=\frac{-7}{25x-50}=\frac{-7}{25\left(x-2\right)}\)( ĐKXĐ : x ≠ 2 )

MTC : \(150\left(x-2\right)\left(x-3\right)\)

9^x-1 = 9

9^x : 9¹ = 9

9^x : 9 = 9

9^x = 9 . 9

9^x = 81

9^x = 9²

Vậy x = 2

Học tốt!!!

9^x-1=9

=>x-1=1

=>x=2

tham khảo link

https://olm.vn/hoi-dap/detail/63038496110.html

\(ĐKXĐ:\hept{\begin{cases}x\ge0\\x\ne1\end{cases}}\)

\(H=\frac{4}{\sqrt{x}+1}+\frac{2}{1-\sqrt{x}}-\frac{\sqrt{x}-5}{x-1}\)

\(=\frac{4}{\sqrt{x}+1}-\frac{2}{\sqrt{x}-1}-\frac{\sqrt{x}-5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{4\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{2\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}-5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{4\sqrt{x}-4}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{2\sqrt{x}+2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}-5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{\left(4\sqrt{x}-4\right)-\left(2\sqrt{x}+2\right)-\left(\sqrt{x}-5\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{4\sqrt{x}-4-2\sqrt{x}-2-\sqrt{x}+5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\frac{1}{\sqrt{x}+1}\)

\(H=\frac{4}{\sqrt{x}+1}+\frac{2}{1-\sqrt{x}}-\frac{\sqrt{x}-5}{x-1}\)

\(=\frac{4\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{2\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}-\frac{\sqrt{x}-5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\frac{4\sqrt{x}-4-2\sqrt{x}-2-\sqrt{x}+5}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\frac{\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\frac{1}{\sqrt{x}+1}\)

đề bài?

Chứng minh rằng với mọi N thuộc Z Thì

A=n ^ 3 - 4n chia hết cho 3

B= 2n ^ 3- 6n ^2 + 16 chia hết cho 12

\(32:\left(3x-2\right)=8\)

\(\left(3x-2\right)=32:8\)

\(3x-2=4\)

\(3x=4+2\)

\(3x=6\)

\(x=6:3=2\)

~GOOD STUDY~

\(2^5:\left(3x-2\right)=2^3\)

\(\Rightarrow3x-2=2^2=4\)

\(\Rightarrow3x=6\)

\(\Rightarrow x=2\)

học tốt^^