Coplete the second sentences so that it has similar meaning to the first sentennces using the correct infinitive type
1, This bike is very big, so Tom can't ride it
This bike is.....to big for Tom to ride..... (example)
2, Jenny must tidy her room
I want..........................................
3, 'I don't think you should go on a diet, Tim'
I advised..............................................
4, Mary gets angry very eassily
Mary tends..............................................
5, She is feeling much better now
she seems ..................................
6, This skirt is very small, so she can't wear it any more
this skirt is...........................................
7, Beatrice felt sleeply, so she didn't watch the end of film
Beatrice felt.............................................
8, It is likely that Julian will win the race again
Julian is.....................................................
9, There is a possibility that she will pass hẻ driving test
It is...........................
10, My mother forrces me to go to bed early every night
My mother makes...........................
11, My advice to you is to take a long holiday
You had...............................................
12, The tea was so hot that I couldn't drink it
The tea was too....................................
13, I don't have the money to buy this blouse
I can't afford........................................................
14, You shouldn't have behaved like that; it was rude of you
It was rude of..........................................................
15, I think you should revise before the test
I advise.........................................................
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Bài làm:
Ta có: \(\frac{a}{b}=\frac{b}{c}\) => \(b^2=ac\)
Thay vào ta được: \(\frac{a^2+b^2}{b^2+c^2}=\frac{a^2+ac}{ac+c^2}=\frac{a\left(a+c\right)}{c\left(a+c\right)}=\frac{a}{c}\)
Vậy \(\frac{a}{c}=\frac{a^2+b^2}{b^2+c^2}\)
Đặt \(\frac{a}{b}=\frac{b}{c}=k\Rightarrow\hept{\begin{cases}a=kb\\b=kc\end{cases}}\Rightarrow a=k^2c\)
\(\frac{a^2+b^2}{b^2+c^2}=\frac{\left(k^2c\right)^2+\left(kc\right)^2}{\left(kb\right)^2+c^2}=\frac{k^4b^c+k^2c^2}{k^2b^2+c^2}=\frac{k^2\left(k^2b^2+c^2\right)}{k^2b^2+c^2}=k^2=\frac{a}{c}\)( đpcm )