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`a)`
`x+(-3/7)=4/7`
`=>x=4/7 -(-3/7)`
`=>x=4/7 + 3/7`
`=>x=7/7`
`=>x=1`
`b)`
`3/2 . x =-2/3`
`=>x=-2/3 : 3/2`
`=>x= -2/3 . 2/3`
`=>x= -4/9`
`c)`
`-5 4/7 : x=13`
`=> -31/7 : x= 13`
`=> x= -31/7 : 13`
`=> x= -13/7 . 1/13`
`=>x=-1/7`
`d)`
`1/2 x - 75% = 1/4`
`=>1/2 x - 3/4 = 1/4`
`=> 1/2 x = 1/4 + 3/4`
`=> 1/2 x = 1`
`=>x= 1 : 1/2`
`=>x=1 . 2/1`
`=>x=2/1`
`=>x=2`
sửa đề
\(\left(4x^2-1\right)\left(x^3+8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x^2-1=0\\x^3+8=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2=\dfrac{1}{4}\\x^3=-8\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\pm\dfrac{1}{2}\\x=-2\end{matrix}\right.\)
\(\left(\dfrac{5}{-7}+\dfrac{-5}{-7}\right)+\dfrac{4}{3}=\left(\dfrac{-5}{7}+\dfrac{5}{7}\right)+\dfrac{4}{3}=0+\dfrac{4}{3}=\dfrac{4}{3}\)
\(\dfrac{10}{3}+\left(\dfrac{10}{-3}+2\right)=\dfrac{10}{3}+\dfrac{-10}{3}+2=0+2=2\)
a: =>3/5x=-1/4-2/5=-13/20
=>x=-13/12
b: =>2/9x=7/9-12/9=-5/9
=>x=-2/5
c: =>3/10-x=6/5
=>x=3/10-12/10=-9/10
d: =>2/3:x=-7-1/3=-22/3
=>x=-22/3:2/3=-22/3x3/2=-11