giảiPhương trình sau (lam đc đến đâu thì lm )
2x -3 = 4x + 6
x ( x- 1 ) = - x ( x + 3 )
3x - 2 (x - 3 ) = 6
( x -1 )^2 = 9 ( x + 1)^2
x - 8 = 3 - 2 ( x + 4 )
( x-2 ) (x + 1) (x - 3) = 0
x ( x^2 - 1) = 0
2x + 6 = 0
( x^2 - 2x + 1 ) -4 = 0
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\(\frac{2a}{2x-3a}-1=0\)
\(\frac{2a-2x+3a}{2x-3a}=0\)
\(\frac{5a-2x}{2x-3a}=0\)
\(5a-2x=0\)
\(5a=2x\)
\(x=\frac{5a}{2}\)
Kết quả \(x=\frac{5a}{2}\left(đúng\right)\)
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