a) x( x - 2 ) + x - 2 = 0

<=> x( x - 2 ) + ( x - 2 ) = 0

<=> ( x - 2 )( x + 1 ) = 0

<=> \(\orbr{\begin{cases}x-2=0\\x+1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)

b) 3x² - 6x = 0

<=> 3x( x - 2 ) = 0

<=> \(\orbr{\begin{cases}3x=0\\x-2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)

c) ( 5x - 4 )² - 49x² = 0

<=> ( 5x - 4 )² - ( 7x )² = 0

<=> ( 5x - 4 - 7x )( 5x - 4 + 7x ) = 0

<=> ( -2x - 4 )( 12x - 4 ) = 0

<=> \(\orbr{\begin{cases}-2x-4=0\\12x-4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{1}{3}\end{cases}}\)

a. 

\(x\left(x-2\right)+x-2=0\) 

\(x\left(x-2\right)+1\left(x-2\right)=0\) 

\(\left(x-2\right)\left(x+1\right)=0\) 

\(\orbr{\begin{cases}x-2=0\\x+1=0\end{cases}}\) 

\(\orbr{\begin{cases}x=2\\x=-1\end{cases}}\) 

b. 

\(3x^2-6x=0\) 

\(3x\left(x-2\right)=0\) 

\(\orbr{\begin{cases}3x=0\\x-2=0\end{cases}}\) 

\(\orbr{\begin{cases}x=0\\x=2\end{cases}}\) 

c. 

\(\left(5x-4\right)^2-49x^2=0\) 

\(\left(5x-4\right)^2-\left(7x\right)^2=0\) 

\(\left(5x-4-7x\right)\left(5x-4+7x\right)=0\) 

\(\left(-2x-4\right)\left(12x-4=0\right)\) 

\(\orbr{\begin{cases}x=-2\\x=\frac{1}{3}\end{cases}}\)

1) x² + x²y - y - 1

= x²( 1 + y ) - ( 1 + y )

= ( 1 + y )( x² - 1 )

= ( 1 + y )( x - 1 )( x + 1 )

2) x² + y² - 2xy - 25

= ( x² - 2xy + y² ) - 25

= ( x - y )² - 5²

= ( x - y - 5 )( x - y + 5 )

3) ( 2x - 1 )( x² + 2x - 1 ) - ( 1 - 2x )( x - 3 )

= ( 2x - 1 )( x² + 2x - 1 ) + ( 2x - 1 )( x - 3 )

= ( 2x - 1 )( x² + 2x - 1 + x - 3 )

= ( 2x - 1 )( x² + 3x - 4 )

= ( 2x - 1 )( x² - x + 4x - 4 )

= ( 2x - 1 )[ x( x - 1 ) + 4( x - 1 ) ]

= ( 2x - 1 )( x - 1 )( x + 4 )

4) a² + x² - 16 + 2ax

= ( a² + 2ax + x² ) - 16

= ( a + x )² - 4²

= ( a + x - 4 )( a + x + 4 )

đây là vật lí nhé

(x²-1)(x²+x+1)(x²-x+1)

=(x²-1)[(x²+1)²-x²]

=(x²-1)[x⁴+2x²+1-x²]

=(x²-1)(x⁴+x²+1)

=(x²)³-1

=x⁶-1

( x² - 1 )( x² + x + 1 )( x² - x + 1 )

= ( x² - 1 )[ ( x² + 1 ) + x ][ ( x² + 1 ) - x ]

= ( x² - 1 )[ ( x² + 1 )² - x² ]

= ( x² - 1 )( x⁴ + 2x² + 1 - x² )

= ( x² - 1 )( x⁴ + x² + 1 )

= x⁶ + x⁴ + x² - x⁴ - x² - 1

= x⁶ - 1 

a) 4a²b³ - 6a³b² = 2a²b²( 2b - 3a )

b) ( a - b )² - ( b - a ) = ( a - b )² + ( a - b ) = ( a - b )( a - b + 1 )

c) ( 8a³ - 27b³ ) - 2a( 4a² - 9b² ) = 8a³ - 27b³ - 8a³ + 18ab² = 18ab² - 27b³ = 9b²( 2a - 3b )

d) 10x² + 10xy + 5x + 5y = 10x( x + y ) + 5( x + y ) = ( x + y )( 10x + 5 ) = 5( x + y )( 2x + 1 )

e) 5ay - 3bx + ax - 15by = 5y( a - 3b ) + x( a - 3b ) = ( a - 3b )( 5y + x )

a) \(4a^2.b^3-6a^3.b^2=2a^2.b^2\left(2b-3a\right)\)

b) \(\left(a-b\right)^2-\left(b-a\right)=\left(a-b\right)^2+\left(a-b\right)\)

\(=\left(a-b\right).\left(a-b+1\right)\)

c) \(8a^3-27b^3-2a.\left(4a^2-9b^2\right)=8a^3-27b^3-8a^3+18ab^2\)

\(=-27b^3+18ab^2=18ab^2-27b^3=9b^2.\left(2a-3b\right)\)

d) \(10x^2+10xy+5x+5y=5.\left(2x^2+2xy+x+y\right)\)

\(=5.\left[\left(2x^2+2xy\right)+\left(x+y\right)\right]=5.\left[2x\left(x+y\right)+\left(x+y\right)\right]\)

\(=5\left(x+y\right)\left(2y+1\right)\)

e) \(5ay-3bx+ax-15by=\left(5ay-15by\right)-\left(3bx-ax\right)\)

\(=5y\left(a-3b\right)-x\left(3b-a\right)=5y\left(a-3b\right)+x\left(a-3b\right)\)

\(=\left(a-3b\right)\left(x+5y\right)\)

trong olm để hỏi các môn liên quan tới học chứ không nên chia sẽ lập trình

Mình nghĩ câu này là Tin học chứ không phải Toán

Cái này mik ko bít làm XD

Sorry!