1, -1/5 + 5/7 - 7/9 + 9/11 - 11/13 - 13/15 - 9/11 + 7/9 - 5/7
2, -1/3 + 3/4 - 4/5 + 5/6 + 6/7 - 7/8 + 6/7 + 5/6 + 4/5 - 3/4
diễn giải ra giúp mh nha
mh đâng cần gấp
mh cảm ơn rất nhiều ạ
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xy+3x-5y=19
=>x(y+3)-5y-15=4
=>(x-5)(y+3)=4
=>\(\left(x-5;y+3\right)\in\left\{\left(1;4\right);\left(4;1\right);\left(-1;-4\right);\left(-4;-1\right);\left(2;2\right);\left(-2;-2\right)\right\}\)
=>\(\left(x;y\right)\in\left\{\left(6;1\right);\left(9;-2\right);\left(4;-7\right);\left(1;-4\right);\left(7;-1\right);\left(3;-5\right)\right\}\)
diện tích trồng cây ăn quả là:
\(1200\times\dfrac{2}{3}=800\left(m^2\right)\)
diện tích trồng hoa là:
\(60:\dfrac{5}{6}=72\left(m^2\right)\)
diện tích trồng rau là:
\(1200-72-800=328\left(m^2\right)\)
tỉ số phần trăm giữa diện tích trồng hoa và diện tích trồng rau là:
72:328\(\times\)100%\(\approx\)22%
A = \(\dfrac{1}{1.2}\) + \(\dfrac{1}{3.4}\) + \(\dfrac{1}{5.6}\) + ... + \(\dfrac{1}{49.50}\)
A < \(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + \(\dfrac{1}{4.5}\) + \(\dfrac{1}{5.6}\) + ... + \(\dfrac{1}{49.50}\)
A < \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{49}-\dfrac{1}{50}\)
A < \(\dfrac{1}{1}-\dfrac{1}{50}\) < 1
A < 1 (đpcm)
1: \(-\dfrac{1}{5}+\dfrac{5}{7}-\dfrac{7}{9}+\dfrac{9}{11}-\dfrac{11}{13}-\dfrac{13}{15}-\dfrac{9}{11}+\dfrac{7}{9}-\dfrac{5}{7}\)
\(=-\dfrac{1}{5}+\left(\dfrac{5}{7}-\dfrac{5}{7}\right)+\left(\dfrac{7}{9}-\dfrac{7}{9}\right)+\left(\dfrac{9}{11}-\dfrac{9}{11}\right)+\left(-\dfrac{11}{13}\right)-\dfrac{13}{15}\)
\(=-\dfrac{1}{5}-\dfrac{1}{13}-\dfrac{13}{15}=-\dfrac{16}{15}-\dfrac{1}{13}=\dfrac{-223}{195}\)
2: \(-\dfrac{1}{3}+\dfrac{3}{4}-\dfrac{4}{5}+\dfrac{5}{6}+\dfrac{6}{7}-\dfrac{7}{8}+\dfrac{6}{7}+\dfrac{5}{6}+\dfrac{4}{5}-\dfrac{3}{4}\)
\(=-\dfrac{1}{3}+\left(\dfrac{3}{4}-\dfrac{3}{4}\right)+\left(\dfrac{4}{5}-\dfrac{4}{5}\right)+\left(\dfrac{5}{6}+\dfrac{5}{6}\right)+\left(\dfrac{6}{7}+\dfrac{6}{7}\right)-\dfrac{7}{8}\)
\(=-\dfrac{1}{3}+\dfrac{5}{3}+\dfrac{12}{7}-\dfrac{7}{8}=\dfrac{4}{3}+\dfrac{12}{7}-\dfrac{7}{8}=\dfrac{365}{168}\)